From a random sample of 25 stores, french bread prices have a mean of $1.50 and a standard deviation of $0.20. What is the lower and upper bounds for a 90% confidence interval of the population mean price.
Round your answer to the nearest hundredth.
Confidence interval for Population mean is given as below:
Confidence interval = Xbar ± t*S/sqrt(n)
From given data, we have
Xbar = 1.5
S = 0.2
n = 25
df = n – 1 = 24
Confidence level = 90%
Critical t value = 1.7109
(by using t-table)
Confidence interval = Xbar ± t*S/sqrt(n)
Confidence interval = 1.5 ± 1.7109*0.2/sqrt(25)
Confidence interval = 1.5 ± 0.0684
Lower limit = 1.5 - 0.0684 = 1.4316
Upper limit = 1.5 + 0.0684 = 1.5684
Confidence interval = (1.4316, 1.5684)
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