Question

From a random sample of 25 stores, french bread prices have a mean of $1.50 and...

From a random sample of 25 stores, french bread prices have a mean of $1.50 and a standard deviation of $0.20. What is the lower and upper bounds for a 90% confidence interval of the population mean price.

Round your answer to the nearest hundredth.

Homework Answers

Answer #1

Confidence interval for Population mean is given as below:

Confidence interval = Xbar ± t*S/sqrt(n)

From given data, we have

Xbar = 1.5

S = 0.2

n = 25

df = n – 1 = 24

Confidence level = 90%

Critical t value = 1.7109

(by using t-table)

Confidence interval = Xbar ± t*S/sqrt(n)

Confidence interval = 1.5 ± 1.7109*0.2/sqrt(25)

Confidence interval = 1.5 ± 0.0684

Lower limit = 1.5 - 0.0684 = 1.4316

Upper limit = 1.5 + 0.0684 = 1.5684

Confidence interval = (1.4316, 1.5684)

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A random sample of 30 boiled peanuts prices are taken. The mean price of the sampled...
A random sample of 30 boiled peanuts prices are taken. The mean price of the sampled boiled peanuts is $6.75 with a sample standard deviation of $1.50. Find a 90% confidence interval for the mean price of all boiled peanuts. Assume the population is normally distributed.
You are given the sample mean and the population standard deviation. Use this information to construct...
You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. From a random sample of 33 business​ days, the mean closing price of a certain stock was ​$111.13. Assume the population standard deviation is ​$10.41. The​ 90% confidence interval is ​( nothing​, nothing​). ​(Round to two decimal places as​ needed.) The​ 95% confidence...
In a random sample of 25 ​people, the mean commute time to work was 33.2 minutes...
In a random sample of 25 ​people, the mean commute time to work was 33.2 minutes and the standard deviation was 7.1 minutes. Assume the population is normally distributed and use a​ t-distribution to construct a 95​% confidence interval for the population mean muμ. What is the margin of error of muμ​? Interpret the results. The confidence interval for the population mean muμ is (____,_______ ) ​(Round to one decimal place as​ needed.) The margin of error of muμ is...
In a random sample of 64 audited estate tax​ returns, it was determined that the mean...
In a random sample of 64 audited estate tax​ returns, it was determined that the mean amount of additional tax owed was ​$3445 with a standard deviation of ​$2593. Construct and interpret a​ 90% confidence interval for the mean additional amount of tax owed for estate tax returns. LOADING... Click the icon to view the​ t-distribution table. The lower bound is ​$ nothing. ​(Round to the nearest dollar as​ needed.) The upper bound is ​$ nothing. ​(Round to the nearest...
In a random sample of 25 ​people, the mean commute time to work was 30.6 minutes...
In a random sample of 25 ​people, the mean commute time to work was 30.6 minutes and the standard deviation was 7.2 minutes. Assume the population is normally distributed and use a​ t-distribution to construct a 95​% confidence interval for the population mean μ. What is the margin of error of μ​? Interpret the results. 1. The confidence interval for the population mean μ is (_,_) 2. The margin of error of μ is __ 3. Interpret the results. A.It...
You are given the sample mean and the population standard deviation. Use this information to construct...
You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. From a random sample of 78 ​dates, the mean record high daily temperature in a certain city has a mean of 85.43 degrees°F. Assume the population standard deviation is 13.72 degrees°F. The​ 90% confidence interval is ​(nothing​,nothing​). ​(Round to two decimal places as​...
You are given the sample mean and the population standard deviation. Use this information to construct...
You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. From a random sample of 72 ​dates, the mean record high daily temperature in a certain city has a mean of 82.800F. Assume the population standard deviation is 15.250F. The​ 90% confidence interval is ​( , ​). ​(Round to two decimal places as​...
A simple random sample of size n is drawn. The sample​ mean, x overbarx​, is found...
A simple random sample of size n is drawn. The sample​ mean, x overbarx​, is found to be 18.4, and the sample standard​ deviation, s, is found to be 4.9 Construct a 95​% confidence interval about muμ if the sample​ size, n, is 35. find lower and upper bounds. Construct a 99​% confidence interval about muμ if the sample​ size, n, is 35 what is the lower and upper bounds?
The prices of a random sample of 24 new motorcycles have a sample standard deviation of...
The prices of a random sample of 24 new motorcycles have a sample standard deviation of $3656. Assume the sample is from a normally distributed population. Construct a confidence interval for the population variance  2 and the population standard deviation . Use a 99% level of confidence. Interpret the results. What is the confidence interval for the population variance  2 ? (____,____) (Round to the nearest integer as needed.) Interpret the results. Select the correct choice below and...
A simple random sample of size n equals n=40 is drawn from a population. The sample...
A simple random sample of size n equals n=40 is drawn from a population. The sample mean is found to be x overbar equals x=121.2 and the sample standard deviation is found to be s equals s=12.4. Construct a​ 99% confidence interval for the population mean. Find the lower and upper bounds.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT