Question

A group of researchers hypothesize that broken bones will take longer to heal among smokers versus...

A group of researchers hypothesize that broken bones will take longer to heal among smokers versus nonsmokers. They test this question with a sample of 20 smokers, where the average time to heal was 32 days (SS = 1161), and a sample of 45 nonsmokers, where the average time to heal was 21 days (SS = 1179). Use the critical-value approach for the appropriate statistical test (where α = .05) to determine if there is a significant difference in bone healing time between smokers and nonsmokers.

1. Identify the alternative hypothesis

2. List your degrees of freedom

3. List your estimated standard error

4. List your t test statistic (where: smokers – nonsmokers)

5. List your critical t value(s)

6. Is the difference in healing time between smokers and nonsmokers statistically significant? (Yes/No)

7. Calculate Cohen’s d for the difference in healing time

Homework Answers

Answer #1

(1)

Ha: Alternative Hypothesis: (The broken bones will take longer to heal among smokers versus nonsmokers. ) (Claim)

(2)

Degrees of Freedom = 20 + 45 - 2 = 63

Our degrees of freedom = 63

(3)

n1 = 20

n2 = 45

1 = 32

2 = 21

Pooled Standard Deviation is given by:

Our estimated standard error = 1.638

(4)

Test Statistic isgiven by:

Our t test statistic = 6.716

(5)

= 0.05'

From Table, critical value of t = 1.669

Our critical t value = 1.669

(6)

Correct option:

Yes

(7)

Cohen's d is given by:

Cohen’s d for the difference in healing time = 1.8051

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The time it takes broken bones of a given size and type to heal is normally...
The time it takes broken bones of a given size and type to heal is normally distributed. A random sample of 17 simple arm breaks occurring in people in their twenties took an average of 50 days to heal with a standard deviation of 5 days. A) Find a 95% confidence interval for the healing time for all broken bones of this type B) Find a 95% confidence interval for the population variance and standard deviation
The time it takes broken bones of a given size & type to heal is normally...
The time it takes broken bones of a given size & type to heal is normally distributed . A random sample of 17 simple arm breaks occurring in people in their twenties took and average of 50 days to heal with a standard deviation of 5 days.) a) Find a 95% confidence interval (ci) for the healing time for all broken bones of this type b) Find a 95% (CI) for the population variance and standard deviation
A group of researchers want to determine if marital satisfaction among women declines following the birth...
A group of researchers want to determine if marital satisfaction among women declines following the birth of a first child. To test this hypothesis, they collected data on marital satisfaction from 22 women at two time points: 6 months after marriage and 1 month after the first child was born. They observed that the average marital satisfaction among women at time 1 was 7.0 and the average marital satisfaction among women at time 2 was 5.8. The sum of squares...
In a recent study, researchers found that Americans spent an average of 5.1 hours on leisure...
In a recent study, researchers found that Americans spent an average of 5.1 hours on leisure per day (306 minutes). You expect that nurses spend significantly less time per day on leisure than the national average. You find in a sample of 43 nurses, the average number of hours of leisure per day was 255 minutes with a standard deviation of 60 minutes. Use the critical-value approach for a t-test (where α = .01) to determine if there is a...
A group of researchers want to determine if there are any significant differences in marital satisfaction...
A group of researchers want to determine if there are any significant differences in marital satisfaction between male and female spouses. To test this hypothesis, they collected data on marital satisfaction from 28 couples (i.e., 28 men and 28 women). They observed that the average marital satisfaction among men was 6.5, and the average among women was 6.0. The sum of squares for the difference scores (SSD) was 440. Additionally, male and female spouse marital satisfaction were strongly related (r...
(Still focusing on the study that found Americans spent an average of 5.1 hours on leisure...
(Still focusing on the study that found Americans spent an average of 5.1 hours on leisure per day). Without any prior expectations, you want to see if aircraft pilots spend different amounts of time per day on leisure than the national average. You find in a sample of 26 pilots, the average amount of leisure time per day was 290 minutes with a standard deviation of 50 minutes. Use the critical-value approach for a t-test (where α = .001) to...
Recently there has been a marketing push promoting the new wave of electronic cigarettes in the...
Recently there has been a marketing push promoting the new wave of electronic cigarettes in the media. Suppose a new study claims that they have determined that e-cigarette smokers still have a much higher risk for esophageal cancer than non-smokers. Assume the following table of summary statistics describes the SRSs of those in the e-cigarette group versus non-smokers. Study Group Average # of cases of esophageal cancer Standard deviation Sample Size E-cigarette Smokers 21.4 1.8 749 Non-Smokers 2.7 0.8 898...
(Still focusing on the study that found Americans spent an average of 5.1 hours on leisure...
(Still focusing on the study that found Americans spent an average of 5.1 hours on leisure per day). Without any prior expectations, you want to see if entrepreneurs spend different amounts of time on leisure per day than the national average. You find in a sample of 30 entrepreneurs, the average amount of leisure time per day was 360 minutes with a standard deviation of 80 minutes. Use a confidence interval (where α = .05) to determine if there is...
(Still focusing on the study that found Americans worked an average of 2,070 minutes per week)....
(Still focusing on the study that found Americans worked an average of 2,070 minutes per week). Without any prior expectations, you want to see if entrepreneurs work different amounts of time per week than the national average. You find in a sample of 12 entrepreneurs, the average amount worked per week was 4,200 minutes with a standard deviation of 1,020 minutes. Use a confidence interval (where α = .001) to determine if there is a significant difference in amount of...
You are interested in on-the-job anxiety among police officers and want to empirically test if the...
You are interested in on-the-job anxiety among police officers and want to empirically test if the shift they work influences their anxiety. You hypothesize that there is a difference in anxiety on the job between police officers who work FIRST shift and police officers who work THIRD shift. You collect data from a large random sample of officers from both shifts. You find that the average on-the-job anxiety for officers who work FIRST shift is 12.8 (std dev = 2.76),...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT