Question

(Still focusing on the study that found Americans spent an average of 5.1 hours on leisure per day). Without any prior expectations, you want to see if aircraft pilots spend different amounts of time per day on leisure than the national average. You find in a sample of 26 pilots, the average amount of leisure time per day was 290 minutes with a standard deviation of 50 minutes. Use the critical-value approach for a t-test (where α = .001) to determine if there is a significant difference in amount of leisure time per day between the national average and pilots. 5. List your degrees of freedom 6. List your t test statistic 7. List your critical t value(s) 8. Is the difference between the national average and working parents statistically significant? (Yes/No)

Answer 1

Ho : = 306 minutes (i.e. 5.1 hours)
Ha : 306 minutes

Level of Significance : α = 0.001

Decision Criteria : Reject Ho at 0.1% l.o.s. if | tcal | > t tab,
where t tab = t ( α/2, n-1 ) = t (0.0005, 25) =  3.725

Calculation :   = 290 minutes, n = 26 &   = 50 minutes

tcal =   =   = -1.6317

Conclusion : Since tcal > t tab, we do not reject Ho at 0.1% l.o.s. & thus, conclude that there is no significant difference between the national average and working parents.

Hope this answers your query!