Question

Create a case (please refer to the sample) on the application of inferences about the difference...

Create a case (please refer to the sample) on the application of inferences about the difference between two population means (σ1 and σ2 known) and explain the hypothesis tests until conclusion.

EXAMPLE:

The mean instant messaging bill is P32.79 per household. A sample of 50 households showed a sample mean of P30.63. Use a population standard deviation of σ=5.60.

Formulate hypothesis for a test to determine whether the sample data support the conclusion that the mean monthly instant messaging bill is less than the national mean of P32.79.

What is the value of the test statistic?

What is the p-value?

At α=0.01, what is your conclusion?

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
I only need answers for number 4 & 5. (Just 2 numbers) 1.) The mean instant...
I only need answers for number 4 & 5. (Just 2 numbers) 1.) The mean instant messaging bill is P32.79 per household. A sample of 50 households showed a sample mean of P30.63. Use a population standard deviation of σ=5.60. Formulate hypothesis for a test to determine whether the sample data support the conclusion that the mean monthly instant messaging bill is less than the national mean of P32.79. What is the value of the test statistic? What is the...
For the United States, the mean monthly Internet bill is $64.79 per household (CNBC, January 18,...
For the United States, the mean monthly Internet bill is $64.79 per household (CNBC, January 18, 2012). A sample of 50 households in a southern state showed a sample mean of $60.63. Use a population standard deviation of σ = $5.60 Formulate hypotheses at the α = 0.01 significance level for a test to determine whether the sample data support the conclusion that the mean monthly Internet bill in the southern state is less than the national mean of $64.79....
Consider the hypothesis test H0: = against H0: > . Suppose that the sample sizes are...
Consider the hypothesis test H0: = against H0: > . Suppose that the sample sizes are n1 = 20 and n2 = 8, and that = 4.5 and = 2.3. Use α = 0.01. Test the hypothesis and explain how the test could be conducted with a confidence interval on σ1/σ2. Refer the question above test the hypothesis and provide your conclusion. At the alpha = 0.01, we fail to reject and conclude that the variances are the same At...
A new kind of typhoid shot is being developed by a medical research team. The old...
A new kind of typhoid shot is being developed by a medical research team. The old typhoid shot was known to protect the population for a mean time of 36 months, with a standard deviation of 3 months. To test the time variability of the new shot, a random sample of 25 people were given the new shot. Regular blood tests showed that the sample standard deviation of protection times was 1.5 months. Using a 0.05 level of significance, test...
Given the information below that includes the sample size (n1 and n2) for each sample, the...
Given the information below that includes the sample size (n1 and n2) for each sample, the mean for each sample (x1 and x2) and the estimated population standard deviations for each case( σ1 and σ2), enter the p-value to test the following hypothesis at the 1% significance level : Ho : µ1 = µ2 Ha : µ1 > µ2   Sample 1 Sample 2 n1 = 10 n2 = 15 x1 = 115 x2 = 113 σ1 = 4.9 σ2 =...
A new kind of typhoid shot is being developed by a medical research team. The old...
A new kind of typhoid shot is being developed by a medical research team. The old typhoid shot was known to protect the population for a mean time of 36 months, with a standard deviation of 3 months. To test the time variability of the new shot, a random sample of 19 people were given the new shot. Regular blood tests showed that the sample standard deviation of protection times was 1.9 months. Using a 0.05 level of significance, test...
A new kind of typhoid shot is being developed by a medical research team. The old...
A new kind of typhoid shot is being developed by a medical research team. The old typhoid shot was known to protect the population for a mean time of 36 months, with a standard deviation of 3 months. To test the time variability of the new shot, a random sample of 23 people were given the new shot. Regular blood tests showed that the sample standard deviation of protection times was 2.1 months. Using a 0.05 level of significance, test...
A new kind of typhoid shot is being developed by a medical research team. The old...
A new kind of typhoid shot is being developed by a medical research team. The old typhoid shot was known to protect the population for a mean time of 36 months, with a standard deviation of 3 months. To test the time variability of the new shot, a random sample of 25 people were given the new shot. Regular blood tests showed that the sample standard deviation of protection times was 1.7 months. Using a 0.05 level of significance, test...
The type of household for the U.S. population and for a random sample of 411 households...
The type of household for the U.S. population and for a random sample of 411 households from a community in Montana are shown below. Type of Household Percent of U.S. Households Observed Number of Households in the Community Married with children 26%         105             Married, no children 29%         120             Single parent 9%         28             One person 25%         91             Other (e.g., roommates, siblings) 11%         67             Use a 5% level of significance to test the claim that the distribution of U.S. households fits the...
The type of household for the U.S. population and for a random sample of 411 households...
The type of household for the U.S. population and for a random sample of 411 households from a community in Montana are shown below. Type of Household Percent of U.S. Households Observed Number of Households in the Community Married with children 26%         103             Married, no children 29%         118             Single parent 9%         34             One person 25%         90             Other (e.g., roommates, siblings) 11%         66             Use a 5% level of significance to test the claim that the distribution of U.S. households fits the...