Question

1. Find the area under the standard normal curve to the left of z = 1.66.

2. Find the area under the standard normal curve between z = -1.75 and z = 0.96.

3. Find the z-score for which the area to its right is 0.67.

4. A normal population has mean 176=m and a standard deviation .38=s What proportion of the population is more than 185?

Answer #1

We know that,

**1.**

**2.**

**3. z-score
**

4**.Given, mean
and standard deviation
**

**The proportion of the population is more than 185 is
0.4064.**

2. a) Find the area under the standard normal curve to the right
of z = 1.5.
b) Find the area under the standard normal curve to the left of
z = 1.
c) Find the area under the standard normal curve to the left of
z = -1.25.
d) Find the area under the standard normal curve between z = -1
and z = 2.
e) Find the area under the standard normal curve between z =
-1.5 and...

Find the indicated area under the standard normal curve.
To the left of z= -1.09 and to the right of z= 1.09
A) The total area to the left of z= −1.09 and to the right of z=
1.09 under the standard normal curve is:_______? (Round to four
deciamal places as needed).

find the area under the standard normal curve to the right z=
1
find the area under the standard normal curve to the left z=
1.25
find the value z(alfa) z0.04

find the area under the standard normal curve to the left of z =
-2.75 and to the right of 2.6. round to four decimal places.

Find the area under the standard normal curve to the left of
z=−2.83 and to the right of z=2.15. Round your answer to four
decimal places, if necessary.

Find the area under the standard normal curve to the left of
z=−2.8 and to the right of z=2.06. Round your answer to four
decimal places, if necessary.

A) What proportion of the area under a normal curve is to the
left of z = -0.44?
B) What proportion of the area under a normal curve is to the
left of z = 0.63?
C) April 10, 2017, was an unseasonably warm day with a
temperature of 82 degrees (Fahrenheit). The mean temperature for
April 13th over the last 50 years is 72 with a standard deviation
of 4.
1. What is the z-score for the temperature on...

Find the z-score such that:
The area under the standard normal model to its left is 0.9412 z
=
The area under the standard normal model to its right is 0.1576
z =

Find the area under the standard normal curve to the left of
z=−1.51z=−1.51 and to the right of z=1.4z=1.4. Round your answer to
four decimal places, if necessary.

Find the value of z if the area under a standard normal curve
(a) to the right of z is 0.3300 (b) to the left of z is .1112, (c)
between 0 and z, with z >0, is ,4803, and (d) between -z and z,
with z > 0, is .9250.

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