Question

(**please explain in TI-84 terms!!)**

A consumer advocacy group received a tip that an air
conditioning company has been charging female customers more than
male customers. The group's statistical expert decides examine this
question at the α=0.05α=0.05 level of significance, by looking at
the difference in mean charges between a random sample of female
customers and a random sample of male customers. Let μFμF represent
the average charges for female customers and μMμM represent the
average charges for male customers.*(Round your results to three
decimal places)*

Which would be correct hypotheses for this test?

- H0:μF−μM=0H0:μF-μM=0, H1:μF−μM<0H1:μF-μM<0
- H0:μF−μM=0H0:μF-μM=0, H1:μF−μM>0H1:μF-μM>0
- H0:μF−μM=0H0:μF-μM=0, H1:μF−μM≠0H1:μF-μM≠0
- HO:μF−μM>0HO:μF-μM>0, H1:μF−μM<0H1:μF-μM<0

If we are going to test this using a confidence interval, which
confidence interval should we construct?

- 95%
- 97.5%
- 90%
- 80%

(**please explain in TI-84 terms!!)**

A random sample of 39 female customers were charged an average of
$1186, with a standard deviation of $10. A random sample of 46 male
customers were charged an average of $1172, with a standard
deviation of $11. Construct the confidence interval:

< μF−μMμF-μM <

Which is the correct result:

- 0 is contained in the confidence interval, so we Do not Reject the Null Hypothesis
- 0 is not contained in the confidence interval, so we Reject the Null Hypothesis
- 0 is contained in the confidence interval, so we Reject the Null Hypothesis
- 0 is not contained in the confidence interval, so we Do not Reject the Null Hypothesis

Which would be the appropriate conclusion?

- There is significant evidence to suggest that the company is charging its female customers more than its male customers.
- There is not significant evidence to suggest that the company is charging its female customers more than its male customers.

LicensePoints possible: 15

This is attempt 1 of 3.

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Answer #1

A consumer advocacy group received a tip that an air
conditioning company has been charging female customers more than
male customers. The group's statistical expert decides examine this
question at the α=0.10α=0.10 level of significance, by looking at
the difference in mean charges between a random sample of female
customers and a random sample of male customers. Let μFμF represent
the average charges for female customers and μMμM represent the
average charges for male customers.(Round your results to three
decimal...

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tests of the mean.
For a two-tailed hypothesis test with level of significance
α and null hypothesis H0: μ =
k, we reject H0 whenever
k falls outside the c = 1 – α
confidence...

Is there a relationship between confidence intervals and
two-tailed hypothesis tests? Let c be the level of
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For a two-tailed hypothesis test with level of significance
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H1:μ>71.84
H0:μ=71.84
H1:μ≠71.84
H0:p=71.84
H1:p≠71.84
H0:p≥71.84
H1:p<71.84
H0:μ≥71.84
H1:μ<71.84
H0:p≤71.84
H1:p>71.84
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Is there a relationship between confidence intervals and
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For a two-tailed hypothesis test with level of significance
α and null hypothesis H0: μ =
k, we reject H0 whenever
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Test H0:(p1?p2)=0 against
Ha:(p1?p2)?0. Use
?=0.07.
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