a)
approximately normal
b)
for normal distribution z score =(X-μ)/σ | |
here mean= μ= | 67 |
std deviation =σ= | 4.5000 |
probability =P(X>71)=P(Z>(71-67)/4.5)=P(Z>0.89)=1-P(Z<0.89)=1-0.8133=0.1867 |
c_)
approximately normal
d_)
mean of the x distribution =67
ii)
std error=σx̅=σ/√n=4.5/√13 = | 1.25 |
e)
probability =P(X>72)=P(Z>(72-67)/1.25)=P(Z>4)=1-P(Z<4)=1-1=0.0000 |
f)
probability =P(X<64)=(Z<(64-67)/1.248)=P(Z<-2.4)=0.0082 |
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