3)
The height of an adult male in the United States is approximately normally distributed with a mean of 69.3 inches and a standard deviation of 2.8 inches.
Find the percentile P90 for the heights of adult males in the United States.
Provided your answer in inches, rounded to 2 decimal places.
Given,
= 69.3 , = 2.8
We convert this to standard normal as
P(X < x) = P(Z < ( x - ) / )
P90 = P(X < x) = 0.90
P(Z< ( x - ) / ) = 0.90
From Z table, z-score for the probability of 0.90 is 1.2816
( x - ) / = 1.2816
(X - 69.3) / 2.8 = 1.2816
Solve for X
X = 72.89
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