Consider the approximately normal population of heights of male college students with mean μ = 69 inches and standard deviation of σ = 3.6 inches. A random sample of 10 heights is obtained.
(a) Describe the distribution of x, height of male college students. skewed right approximately normal skewed left chi-square
(b) Find the proportion of male college students whose height is greater than 71 inches. (Give your answer correct to four decimal places.)
(c) Describe the distribution of x, the mean of samples of size 10. skewed right approximately normal skewed left chi-square
(d) Find the mean of the x distribution. (Give your answer correct to the nearest whole number.)
(ii) Find the standard error of the x distribution. (Give your answer correct to two decimal places.)
(e) Find P(x > 67). (Give your answer correct to four decimal places.)
(f) Find P(x < 66). (Give your answer correct to four decimal places.)
a) Normal
b) P(X < A) = P(Z < (A - mean)/standard deviation)
P(X > 71) = 1 - P(X < 71)
= 1 - P(Z < (71 - 69)/3.6)
= 1 - P(Z < 0.56)
= 1 - 0.7123
= 0.2877
c) Normal (according to Central Limit Theorem)
d) (i) Mean = 69 inches
(ii) Standard error =
=
= 1.14
e) For sampling distribution of mean, P(x < A) = P(Z < (x - mean)/standard error)
P(x > 67) = 1 - P(x < 67)
= 1 - P(Z < (67 - 69)/1.14)
= 1 - P(Z < -1.75)
= 1 - 0.0401
= 0.9599
f) P(x < 66)
= P(Z < (66 - 69)/1.14)
= P(Z < -2.63)
= 0.0043
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