in a doctors office, the probability of a "no show" patient for any checkup appointment on any given day is 1 out of 10. suppose that there are 18 appointments scheduled for one day. find the probability that at least 2 patients done show. please include how to solve on ti84
Let X is a random variable shows the number of patients who dont shows. Here X has binomial distribution with parameters as follows:
n=18 and p=1/10 = 0.10
We need to find the probability .
In calculator, press 1 - . Then press 2nd-Vars. Then select binomcdf and enter values. Then press enter. Following is the screen shot:
So the probability that at least 2 patients done show is 0.5497.
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