Age range (yr) | 20-29 | 30-39 | 40-49 | 50-59 | 60-69 | 70-79 | 80+ |
Midpoint x | 24.5 | 34.5 | 44.5 | 54.5 | 64.5 | 74.5 | 84.5 |
Percent of nurses | 5.6% | 9.1% | 19.3% | 29.7% | 24.5% | 10.1% | 1.7% |
What was the age distribution of nurses in Great Britain at the time of Florence Nightingale? Suppose we have the following information. Note: In 1851 there were 25,466 nurses in Great Britain.
Compute the standard deviation σ for ages of nurses shown in the distribution. (Round your answer to two decimal places.)
Solution :
x | P(x) | x * P(x) | x2 * P(x) |
24.5 | 0.056 | 1.372 | 33.614 |
34.5 | 0.091 | 3.1395 | 108.3128 |
44.5 | 0.193 | 8.5885 | 382.1883 |
54.5 | 0.297 | 16.1865 | 882.1643 |
64.5 | 0.245 | 15.8025 | 1019.261 |
74.5 | 0.101 | 7.5245 | 560.5753 |
84.5 | 0.017 | 1.4365 | 121.3843 |
Sum | 1 | 54.05 | 3107.5 |
Mean = = X * P(X) = 54.05
Standard deviation =
=X 2 * P(X) - 2
= (3107.5 - 54.052)
= 13.64
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