1) Let X denote the event that 2 dice are the same then, there are six possible cases. While if Y denotes the number of pairs which sum up to eight is 5 which are {(2,6),(3,5),(4,4),(5,3),(6,2)}. Then the probability that 2 dice are the same or the sum of 8 is P(X or Y) =P(X) + P(Y) - P(X and Y) = 6/36 + 5/36 -1/36 = 10/36
2) The number of ways in which the positions can be filled with 3 females and 2 males is
3) There are two cases:
case 1: the first ball drawn is green: then probability than 2nd ball is green=
case 2: the first ball is orange: hen probability than 2nd ball is green=
Hence, the probability than 2nd ball is green= 1/12 + 1/4 = 1/3
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