Question

A bag contains 3 red marbles, 5 blue marbles, 8 yellow marbles, and 7 green marbles. What is the probability of choosing a yellow or green marble when one marble is drawn?

Answer #1

**If events A and B are mutually exclusive, then the
probability of A or B is simply:**

**P(A or B) = P(A) + P(B)**

Number of Red Marbles = 3

Number of Blue Marbles = 5

Number of Yellow Marbles = 8

Number of Green Marbles = 7

Total Number of Marbles = 23

P(Green Marble) =

P(Yellow Marble) =

We have to find the probability of choosing a yellow or green marble when one marble is drawn.Since it is impossible to get both a Yellow Marble and a Green Marble, these two events are mutually exclusive. these two events are mutually exclusive. Therefore,

P(Yellow Marble or Green Marble) = P(Yellow Marble) + P(Green Marble) =

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