Question

A bag contains 3 red marbles, 5 blue marbles, 8 yellow marbles, and 7 green marbles. What is the probability of choosing a yellow or green marble when one marble is drawn?

Answer #1

Solution :

Since, drawing a yellow marble and drawing a green marbls are mutually exclusive events, therefore

P(yellow or green) = P(yellow) + P(green)

P(yellow) = Number of yellow marbles/Total number of marbles

P(yellow) = 8/23

P(green) = Number of green marbles/Total number of marbles

P(green) = 7/23

Hence,

P(yellow or green) = (8/23) + (7/23)

P(yellow or green) = 15/23

P(yellow or green) = 0.6522

**Hence, the probability of choosing a yellow or green
marble when one marble is drawn is 0.6522**.

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