An engineer is comparing voltages for two types of batteries (K and Q) using a sample of 89 type K batteries and a sample of 103 type Q batteries. The type K batteries have a mean voltage of 8.51, and the population standard deviation is known to be 0.312. The type Q batteries have a mean voltage of 8.77, and the population standard deviation is known to be 0.779. Conduct a hypothesis test for the conjecture that the mean voltage for these two types of batteries is different. Let μ1 be the true mean voltage for type K batteries and μ2 be the true mean voltage for type Q batteries. Use a 0.05 level of significance.
Step 1 of 5 : State the null and alternative hypotheses for the test.
Step 2 of 5: Compute the value of the test statistic. Round your answer to two decimal places.
Step 3 of 5: Find the p-value associated with the test statistic. Round your answer to four decimal places.
Step 4 of 5: reject or fail to reject the null hypothersis?
Step 5 of 5: do we have sufficient evidence or insufficient evidence?
The statistical software output for this problem is :
H0 : μ1 - μ2 = 0 , HA : μ1 - μ2 ≠ 0
Test statistics = -3.11
P-value = 0.0019
Reject the null hypothesis
sufficient evidence
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