Question

Chicken Delight claims that 96% of its orders are delivered
within 10 minutes of the time the order is placed. A sample of 70
orders revealed that 64 were delivered within the promised time. At
the 0.01 significance level, can we conclude that less than 96% of
the orders are delivered in less than 10 minutes?

(a) What is the decision rule? (Negative amount should be indicated
by a minus sign. Round your answer to 2 decimal places.)

Reject Ho if z < ________

(b) Compute the value of the test statistic. (Negative amount
should be indicated by a minus sign. Round the intermediate values
and final answer to 2 decimal places.)

Value of the test statistic ________

Answer #1

Here using ti-83 calculator.

a)

Using z-table.

Alpha = 0.01

Reject H0 if z < -2.33

b)

Test statistic :-

z = -1.95

Do not reject the null hypothesis (H0).

Therefore, there is not enough evidence to conclude that

less than 96% of the orders are delivered in less than 10 minutes.

Chicken Delight claims that 92% of its orders are delivered
within 10 minutes of the time the order is placed. A sample of 80
orders revealed that 70 were delivered within the promised time. At
the 0.01 significance level, can we conclude that less than 92% of
the orders are delivered in less than 10 minutes?
A.) What is the decision rule? (Negative amount should
be indicated by a minus sign. Round your answer to 2 decimal
places.)
B.) Compute...

Chicken Delight claims that 64% of its orders are delivered
within 10 minutes of the time the order is placed. A sample of 100
orders revealed that 58 were delivered within the promised time. At
the 0.10 significance level, can we conclude that less than 64% of
the orders are delivered in less than 10 minutes?
a. What is your decision regarding the below
hypothesis? (Round the final answer to 2 decimal
places.)
H0 is rejected if z
< ...

Chicken Delight claims that 90% of its orders are delivered
within 10 minutes of the time the
order is placed. A sample of 100 orders revealed that 92 were
delivered within the promised
time. At the .10 significance level, can we conclude that more than
90% of the orders are
delivered in less than 10 minutes?

Question 1
Part (a)
Chicken Delight claims that at least 90 percent of its orders are
delivered within 5 minutes of the time the order was placed. A
sample of 50 orders revealed that 42 of them were delivered within
5 minutes. Using a level of significance of 0.05, carry out a
hypothesis test for Chicken Delight’s claim.
Part (b)
What percentage of orders was delivered within 5 minutes in Part
(a)?
Part (c)
What is the decision regarding H0...

A national grocer’s magazine reports the typical shopper spends
7 minutes in line waiting to check out. A sample of 17 shoppers at
the local Farmer Jack’s showed a mean of 6.4 minutes with a
standard deviation of 4.3 minutes.
Is the waiting time at the local Farmer Jack’s less than that
reported in the national magazine? Use the 0.050 significance
level.
What is the decision rule? (Negative amount should be
indicated by a minus sign. Round your answer to...

A national grocer’s
magazine reports the typical shopper spends 8 minutes in line
waiting to check out. A sample of 18 shoppers at the local Farmer
Jack’s showed a mean of 7.1 minutes with a standard deviation of
2.7 minutes.
Is the waiting time at
the local Farmer Jack’s less than that reported in the national
magazine? Use the 0.100 significance level.
What is the decision rule? (Negative amount should be
indicated by a minus sign. Round your answer to...

1-) A national grocer’s magazine reports the typical shopper
spends 9.5 minutes in line waiting to check out. A sample of 27
shoppers at the local Farmer Jack’s showed a mean of 9.1 minutes
with a standard deviation of 2.2 minutes.
Is the waiting time at the local Farmer Jack’s less than that
reported in the national magazine? Use the 0.010 significance
level.
What is the decision rule? (Negative amount should be
indicated by a minus sign. Round your answer...

The management of White Industries is considering a new method
of assembling its golf cart. The present method requires 62.3
minutes, on the average, to assemble a cart. The mean assembly time
for a random sample of 20 carts, using the new method, was 60.6
minutes, and the standard deviation of the sample was 3.1 minutes.
Using the 0.02 level of significance, can we conclude that the
assembly time using the new method is faster?
a. What is the decision...

The management of White Industries is considering a new method
of assembling its golf cart. The present method requires 50.3
minutes, on the average, to assemble a cart. The mean assembly time
for a random sample of 60 carts, using the new method, was 48.6
minutes, and the standard deviation of the sample was 2.8
minutes.
Using the 0.10 level of significance, can we conclude that the
assembly time using the new method is faster?
a. What is the decision...

Watch Corporation of Switzerland claims that its watches on
average will neither gain nor lose time during a week. A sample of
18 watches provided the following gains (+) or losses (-) in
seconds per week. Is it reasonable to conclude that the mean gain
or loss in time for the watches is 0?
0.10
0.30
0.40
-0.32
-0.20
-0.23
0.40
0.25
-0.10
-0.37
-0.61
-0.10
-0.20
-0.64
0.30
-0.20
-0.68
-0.30
(a) State the decision rule for 0.01 significance...

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