Question

A survey claims that the average cost of a hotel room in tulsa, oklahoma, is less...

A survey claims that the average cost of a hotel room in tulsa, oklahoma, is less than $49.21. ... Your question has been answered Let us know if you got a helpful answer. Rate this answer Question: A survey claims that the average cost of a hotel room in Tulsa, Oklahoma, is less than $49.21. In... See this question in the app A survey claims that the average cost of a hotel room in Tulsa, Oklahoma, is less than $49.21. In order to test this claim, a researcher selects a sample of 26 hotel rooms and finds the average cost equal to $47.37 with a sample standard deviation of $6.42. Assume the population random variable is normal. At alpha=.1. What is the p-value of the test.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The average cost of a hotel room in NYC is $168 per night. A random sample...
The average cost of a hotel room in NYC is $168 per night. A random sample of 25 hotel rooms resulted in X = $172.50 and s = $15.40. Test the claim at the 0.05 level.
A state executive claims that the average cost of tuition at public colleges is $5700. A...
A state executive claims that the average cost of tuition at public colleges is $5700. A researcher wishes to test the claim that this cost is greater than $5700. She selects a random sample of 36 public colleges and finds the mean to be $5950.The population standard deviation is $659. Is there enough evidence to support the claim that the cost of tuition is greater than $5700 at α = 0.05 ?
Question 1 (15 Marks) The average cost per night of a hotel room in New York...
Question 1 The average cost per night of a hotel room in New York City is $273 (SmartMoney, March 2009). Assume this estimate is based on a sample of 45 hotels and that the sample standard deviation is $65. a. With 95% confidence, what is the margin of error? b. What is the 95% confidence interval estimate of the population mean? c. Two years ago the average cost of a hotel room in New York City was $229. Discuss the...
1. (CO 7) A travel analyst claims that the mean room rates at a three-star hotel...
1. (CO 7) A travel analyst claims that the mean room rates at a three-star hotel in Chicago is greater than $152. In a random sample of 36 three-star hotel rooms in Chicago, the mean room rate is $163 with a standard deviation of $41. At α=0.10, what type of test is this and can you support the analyst’s claim using the p-value? Claim is the alternative, fail to reject the null as p-value (0.054) is less than alpha (0.10),...
A hospital claims that its emergency room has an average wait time of 2 hours (120...
A hospital claims that its emergency room has an average wait time of 2 hours (120 minutes). After a visit to their ER when we had to wait for what seemed like an eternity, we decide to test the hospital's claim because we think their claim of an average of two hours is way too low. We survey people as they exit the ER. From our sample of 58 people, we get a mean wait time of 128 minutes with...
A researcher wished to compare the average daily hotel room rates between San Francisco and Los...
A researcher wished to compare the average daily hotel room rates between San Francisco and Los Angeles. The researcher obtained an SRS of 15 hotels in downtown San Francisco and found the sample mean x1=$156 , with a standard deviation s1= $15 . The researcher also obtained an independent SRS of 10 hotels in downtown Los Angeles and found the sample mean x2= $143, with a standard deviation s2=$10. Let 1 and 2 represent the mean cost of the populations...
Many people claimed that the average cost of living for grocery expenses for family with one...
Many people claimed that the average cost of living for grocery expenses for family with one or two children in the Washington D.C metropolitan is exceeded $1,200 per month. In a sample of 100 family survey undertaken in the Washington D.C metropolitan area in July 2019. The average cost and standard deviation of living for grocery expenses for family with one or two children in the Washington D.C metropolitan are found to be $1,380 and $190, respectively. Do these data...
A marketing manager claims that the average 18-25 year old watches Netflix less than 26 hours...
A marketing manager claims that the average 18-25 year old watches Netflix less than 26 hours per week. She collects data on 25 individuals' in the age range and interviews them about their Netflix habits. She finds that the mean number of hours that the sample spent watching Netflix was 22.4 hours. If the population standard deviation is known to be eight hours, can we conclude at the 1% significance level that she is right? State the null and alternative...
3. Insurance company A claims that its customers pay less for car insurance, on average, than...
3. Insurance company A claims that its customers pay less for car insurance, on average, than customers of its competitor, Company B. You wonder if this is true, so you decide to compare the average monthly costs of similar insurance policy from the two companies. For a random sample of 9 people who buy insurance from company A, the mean cost is $152 per month with a sample standard deviation of $17. For 11 randomly selected customers of company B,...
A "sleep habits" survey answered by 23 randomly selected New Yorkers contained the question "How much...
A "sleep habits" survey answered by 23 randomly selected New Yorkers contained the question "How much sleep do you get per night?" The sample average was 7.75 hours, with a corresponding sample standard deviation of 0.8 hours. Conduct a hypothesis test to see if there is evidence that New Yorkers (who live, after all, in "the city that never sleeps") on average get less than 8 hours of sleep per night, using α=0.05. a. The t test statistic is:   Round...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT