Question

3. Insurance company A claims that its customers pay less for car insurance, on average, than...

3. Insurance company A claims that its customers pay less for car insurance, on average, than customers of its competitor, Company B. You wonder if this is true, so you decide to compare the average monthly costs of similar insurance policy from the two companies. For a random sample of 9 people who buy insurance from company A, the mean cost is $152 per month with a sample standard deviation of $17. For 11 randomly selected customers of company B, you find that they pay a mean of $155 per month with a sample standard deviation of $14. Assume that the population variances are not equal, and test Company A’s claim at the 0.01 level of significant. State the Hyp: Test Value is_____=______ P-value = ________ Decision:__________________________________________________

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
7. A wireless company claims that the average of the customers cell phone bill is less...
7. A wireless company claims that the average of the customers cell phone bill is less than $90.00 per month. A sample of 75 customers reported that their average monthly bill is $84.25 with a standard deviation of $16.03. Test the claim at ∝= 0.005
Question-A cosmetic company claims that its customers spend an average of more than $3,000 a year...
Question-A cosmetic company claims that its customers spend an average of more than $3,000 a year on makeup. A random sample of 60 customers gave a mean of $3,250 with a standard deviation of $1,620. At ? =0.10, can you conclude than the mean customer spending on makeup is more than $3,000? Show all steps of the hypothesis test: Hypotheses, Alpha, Distribution, Sketch with Critical Value, Calculate Test Statistic by hand and put on Sketch, Decision, Conclusion.
A car insurance company advertises that customers switching to their insurance save, on average, £432 on...
A car insurance company advertises that customers switching to their insurance save, on average, £432 on their yearly premiums. A market researcher at a competing insurance discounter is interested in showing that this value is an overestimate so he can provide evidence to government regulators that the company is falsely advertising their prices. He randomly samples 82 customers who recently switched to this insurance and finds an average savings of £395, with a standard deviation of £102. (a) What are...
A company claims that the average monthly expenditure of its customers is greater than $175. The...
A company claims that the average monthly expenditure of its customers is greater than $175. The results of a sample of customers’ monthly expenditures is below. ?̅= 176, ? = 10, ? = 50 At ? = 0.01 , is there enough evidence to support the company’s claim? 1). State the hypothesis and label which represents the claim: : H 0 : H a 2). Specify the level of significance  = 3). Sketch the appropriate distribution and label it...
A car manufacturer, Swanson, claims that the mean lifetime of one of its car engines is...
A car manufacturer, Swanson, claims that the mean lifetime of one of its car engines is greater than 220000 miles, which is the mean lifetime of the engine of a competitor. The mean lifetime for a random sample of 23 of the Swanson engines was with mean of 226450 miles with a standard deviation of 11500 miles. Test the Swanson’s claim using a significance level of 0.01. What is your conclusion?
A water supplying company wishes to estimate the average amount that private customers pay per month....
A water supplying company wishes to estimate the average amount that private customers pay per month. A random sample of 25  customers' bills during a given month produced a sample mean of $30, and a sample standard deviation of $5. (So, the current problem differs from the previous. In the previous problem, $5 presented the standard deviation for the whole population, while in these problem, $5 is the standard deviation on; only for a sample of 25 customers.)   a) Without any...
A sporting goods store believes the average age of its customers is 38 or less. A...
A sporting goods store believes the average age of its customers is 38 or less. A random sample of 45 customers was​ surveyed, and the average customer age was found to be 42.1 years. Assume the standard deviation for customer age is 9.0 years. Using alpha equals 0.01​, determine the p value for this test.
At a certain university, the average cost of books per student was $390 per student last...
At a certain university, the average cost of books per student was $390 per student last semester. In a sample of 35 students this semester, their average cost was $410. Assume the population standard deviation is $90. The Dean of Students claims that the costs are greater this semester. Test the dean’s claim at α=0.05 level of significance. State the Hyp: Test Value is_____=______ P-value = ________ Decision:______ Conclusion
5. A car dealer claims that the average wait time for an oil change is less...
5. A car dealer claims that the average wait time for an oil change is less than 30 minutes. The population of wait times is normally distributed and 26 customers are sampled. The sample mean is 28.7 minutes and the standard deviation of the sample is 2.5 minutes. Test the claim at the .05 significance level (α=.05) using the traditional method.
A manufacturer claims that the mean driving cost per mile of its minivans is less than...
A manufacturer claims that the mean driving cost per mile of its minivans is less than that of its minivans is less than that of its leading competitor. You conduct a study using 34 randomly selected minivans from the manufacture and 38 from the leading competitor. The results are shown at the right. At alpha = 0.10, can you support the manufacturer’s claim? Assume the population variances are equal. manufactuer x1= $0.52/ mi s1= $0.08/ mi n1= 34 competitor x2=...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT