Question

NOTE: Answers using *z*-scores rounded to 3 (or more)
decimal places will work for this problem.

The population of weights for men attending a local health club is
normally distributed with a mean of 183-lbs and a standard
deviation of 27-lbs. An elevator in the health club is limited to
34 occupants, but it will be overloaded if the total weight is in
excess of 6630-lbs.

Assume that there are 34 men in the elevator. What is the average
weight beyond which the elevator would be considered
overloaded?

average weight = lbs

What is the probability that one randomly selected male health club
member will exceed this weight?

P(one man exceeds) =

(Report answer accurate to 4 decimal places.)

If we assume that 34 male occupants in the elevator are the result
of a random selection, find the probability that the evelator will
be overloaded?

P(elevator overloaded) =

(Report answer accurate to 4 decimal places.)

If the evelator is full (on average) 6 times a day, how many times
will the evelator be overloaded in one (non-leap) year?

number of times overloaded =

(Report answer rounded to the nearest whole number.)

Is there reason for concern?

- no, the current overload limit is adequate to insure the safety of the passengers
- yes, the current overload limit is not adequate to insure the safey of the passengers

Answer #1

1) average weight =6630/34= **195**

2)

probability that one randomly selected male health club member will exceed this weight :

probability
=P(X>195)=P(Z>(195-183)/27)=P(Z>0.44)=1-P(Z<0.44)=1-0.67=0.3300 |

3)

sample size =n= | 34 |

std error=σ_{x̅}=σ/√n= |
4.6305 |

probability
=P(X>195)=P(Z>(195-183)/4.63)=P(Z>2.59)=1-P(Z<2.59)=1-0.9952=0.0048 |

4)

expected number of times =6*365*0.0048 =10.51 ~11

yes, the current overload limit is not adequate to insure the safey of the passengers

NOTE: Answers using z-scores rounded to 3 (or more)
decimal places will work for this problem.
The population of weights for men attending a local health club is
normally distributed with a mean of 170-lbs and a standard
deviation of 28-lbs. An elevator in the health club is limited to
33 occupants, but it will be overloaded if the total weight is in
excess of 6171-lbs.
Assume that there are 33 men in the elevator. What is the average
weight...

NOTE: Answers using z-scores rounded to 3 (or more)
decimal places will work for this problem.
The population of weights for men attending a local health club is
normally distributed with a mean of 180-lbs and a standard
deviation of 29-lbs. An elevator in the health club is limited to
35 occupants, but it will be overloaded if the total weight is in
excess of 6825-lbs.
Assume that there are 35 men in the elevator. What is the average
weight...

NOTE: Answers using z-scores rounded to 3 (or more) decimal
places will work for this problem. The population of weights for
men attending a local health club is normally distributed with a
mean of 174-lbs and a standard deviation of 31-lbs. An elevator in
the health club is limited to 34 occupants, but it will be
overloaded if the total weight is in excess of 6460-lbs. Assume
that there are 34 men in the elevator. What is the average weight...

NOTE: Answers using z-scores rounded to 3 (or more)
decimal places will work for this problem.
The population of weights for men attending a local health club is
normally distributed with a mean of 167-lbs and a standard
deviation of 26-lbs. An elevator in the health club is limited to
33 occupants, but it will be overloaded if the total weight is in
excess of 5841-lbs.
Assume that there are 33 men in the elevator. What is the average
weight...

NOTE: Answers using z-scores rounded to 2 (or more) decimal
places will work for this problem. The population of weights for
men attending a local health club is normally distributed with a
mean of 171-lbs and a standard deviation of 31-lbs. An elevator in
the health club is limited to 35 occupants, but it will be
overloaded if the total weight is in excess of 6510-lbs. Assume
that there are 35 men in the elevator. What is the average weight...

The population of weights for men attending a local health club
is normally distributed with a mean of 174-lbs and a standard
deviation of 28-lbs. An elevator in the health club is limited to
33 occupants, but it will be overloaded if the total weight is in
excess of 6204-lbs. Assume that there are 33 men in the elevator.
What is the average weight beyond which the elevator would be
considered overloaded? average weight = lbs What is the probability...

NOTE: Answers using z-scores rounded to 3 (or more)
decimal places will work for this problem.
The population of weights for men attending a local health club is
normally distributed with a mean of 167-lbs and a standard
deviation of 27-lbs. An elevator in the health club is limited to
32 occupants, but it will be overloaded if the total weight is in
excess of 5824-lbs.
Assume that there are 32 men in the elevator. What is the average
weight...

The
population of weights for Mann attending a local health club is
normally distributed with a mean of 168-lbs and a standard
deviation of 27lbs. an elevator in the health club is limited to 32
occupants but it will overload if the total weight is in excess of
5824-lbs.
What is the probability that one randomly selected male health
club member will exceed this weight? Report your answer accurate to
the four decimal place. p(one man exceeds)=______
If we assume...

The population of weights for men attending a local health club
is normally distributed with a mean of 170-lbs and a standard
deviation of 29-lbs. An elevator in the health club is limited to
32 occupants, but it will be overloaded if the total weight is in
excess of 5952-lbs.
Assume that there are 32 men in the elevator. What is the average
weight beyond which the elevator would be considered
overloaded?
average weight = lbs
What is the probability that...

A company produces steel rods. The lengths of the steel rods are
normally distributed with a mean of 133.8-cm and a standard
deviation of 0.6-cm. For shipment, 8 steel rods are bundled
together.
Find the probability that the average length of a randomly selected
bundle of steel rods is between 133.8-cm and 134.2-cm.
P(133.8-cm < M < 134.2-cm) =
Enter your answer as a number accurate to 4 decimal places. Answers
obtained using exact z-scores or z-scores rounded
to 3...

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 36 minutes ago

asked 36 minutes ago

asked 41 minutes ago

asked 54 minutes ago

asked 58 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 3 hours ago

asked 3 hours ago