Mr. James McWhinney, president of Daniel-James Financial
Services, believes there is a relationship between the number of
client contacts and the dollar amount of sales. To document this
assertion, Mr. McWhinney gathered the following sample information.
The X column indicates the number of client contacts last month,
and the Y column shows the value of sales ($ thousands) last month
for each client sampled. (Round the final answers to 2 decimal
places.)
Number of
Contacts,
X Sales
($ thousands),
Y Number of
Contacts,
X Sales
($ thousands),
Y
14 $24 23 $30
12 14 48 90
20 28 50 85
16 30 55 120
46 80 50 110
b. Suppose a large sample is selected (instead of just 10). About
95% of the predictions regarding sales would occur between what two
values? Assuming that the Standard Error of Estimate does not
change. Use z = 2.
X | Y | |||
14 | 24 | mean | 61.1 | |
12 | 14 | Std. Dev | 39.78959 | |
20 | 28 | Z | 2 | |
16 | 30 | n | 10 | |
46 | 80 | Std. Dev/sqrt(n) | 12.58257 | |
23 | 30 | |||
48 | 90 | Z*SE | 25.16514 | |
50 | 85 | |||
55 | 120 | lower | 35.93486 | |
50 | 110 | upper | 86.26514 |
Ans: Please look at the table for values
For the population, about 95% values fall between
Based on the sample,
z is given as 2
n = 10
Standard error = SE =
Hence, the range= [61.1 - 2*12.58 , 61.1 + 2*12.58]
= [35.93, 86.26]
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