In a survey of 1060 Canadian adults, 770 say that the energy situation in Canada is very or fairly serious.
1. Find the point estimate for the population proportion.
2. Construct a 95% confidence interval for the population proportion.
(a) The critical value:
(b) The margin of error
(c) The lower limit of the interval:
(d) The upper limit of the interval:
3. find the minimum sample size needed to estimate the population proportion at the 99% confidence level in order to ensure that the estimate is accurate within 5 % of the population proportion.
(a) The critical value:
(b) The margin of error:
(c) The sample size:
Solution :
Given that,
n = 1060
x = 770
1) Point estimate = sample proportion = = x / n = 770 / 1060 = 0.726
1 - = 1 - 0.726 = 0.274
2)a) At 95% confidence level
= 1 - 95%
=1 - 0.95 =0.05
/2
= 0.025
Z/2
= Z0.025 = 1.960
b) Margin of error = E = Z / 2 * (( * (1 - )) / n)
= 1.96 (((0.726 * 0.274) / 1060 )
= 0.027
A 95% confidence interval for population proportion p is ,
c) lower limit = - E
lower limit = 0.726 - 0.027
lower limit = 0.699
d) upper limit = + E
upper limit = 0.726 + 0.027
upper limit = 0.753
3) a) At 99% confidence level
= 1 - 99%
= 1 - 0.99 =0.01
/2
= 0.05
Z/2
= Z0.005 = 2.576
b) margin of error = E = 0.05
c) sample size = n = (Z / 2 / E )2 * * (1 - )
= (2.576 / 0.05 )2 * 0.726 * 0.274
= 528.006
sample size = n = 529
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