In a survey of 1030 Canadian adults, 720 say that the energy situation in Canada is very or fairly serious.
1. Find the point estimate for the population proportion.
2. Construct a 95% confidence interval for the population proportion.
(a) The critical value:
(b) The margin of error:
(c) The lower limit of the interval:
(d) The upper limit of the interval:
3. find the minimum sample size needed to estimate the population proportion at the 99% confidence level in order to ensure that the estimate is accurate within 3 % of the population proportion.
(a) The critical value:
(b) The margin of error:
(c) The sample size:
Solution :
Given that,
n = 1030
x = 720
1) Point estimate = sample proportion = = x / n = 720 / 1030 = 0.699
1 - = 1 - 0.699 = 0.301
2) a) At 95% confidence level
= 1 - 95%
=1 - 0.95 =0.05
/2
= 0.025
Z/2
= Z0.025 = 1.960
b) Margin of error = E = Z / 2 * (( * (1 - )) / n)
= 1.96 (((0.699 * 0.301) / 1030)
= 0.028
A 95% confidence interval for population proportion p is ,
± E
= 0.699 ± 0.028
= ( 0.671, 0.727 )
c) lower limit = 0.671
d) upper limit = 0.727
3)a) At 99% confidence level
= 1 - 99%
= 1 - 0.99 =0.01
/2
= 0.005
Z/2
= Z0.005 = 2.576
b) Margin of error = E = 0.03
c) sample size = n = (Z / 2 / E )2 * * (1 - )
= (2.576 / 0.03)2 * 0.699 * 0.301
= 1551.28
sample size = n = 1552
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