In a recent awards ceremony, the age of the winner for best actor was
29
and the age of the winner for best actress was
50.
For all best actors, the mean age is
43.9
years and the standard deviation is
8.7
years. For all best actresses, the mean age is
37.5
years and the standard deviation is
12.2
years. (All ages are determined at the time of the awards ceremony.) Relative to their genders, who had the more extreme age when winning the award, the actor or the actress? Explain.
Solution :
Given that ,
mean = = 43.9 ( actors)
standard deviation = = 8.7
x = 29
Using z-score formula,
z = x - /
z = 29 - 43.9 / 8.7
z = -1.71 ( actors)
mean = = 37.5 ( actresses)
standard deviation = = 12.2
x = 50
Using z-score formula,
z = x - /
z = 50 - 37.5 / 12.2
z = 1.02 ( actresses)
Since the z-score for the actor is z = -1.71 and the z-score for the actresses is z = 1.02, the actresses had the more extreme age
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