Question

Show all work. Check your work with a calculator. Researchers are interested in understanding the weekend...

Show all work. Check your work with a calculator.

  1. Researchers are interested in understanding the weekend spending habits of college students. A simple random sample of 1500 college students is taken from universities across the United States. The average amount of money spent on the weekends was $95 with a standard deviation of $185. Construct a 95% confidence interval for the spending habits of college students on the weekends. Interpret your results. Round to the nearest hundredths.
  1. Researchers are interested in understanding the number of ounces of baby food that children who are 6 months old consume in a day. A simple random sample of 22 6-month old’s is taken. The average number of ounces was 5.8 with a sample standard deviation of 1.63. Construct a 95% confidence interval for the number of ounces of baby food consumed in a day. Interpret your results. Round to the nearest hundredths.
  1. Researchers are interested in studying the cholesterol levels of heart disease patients. A simple random sample of 28 patients with heart disease is taken. The mean cholesterol level was 261.59 with a sample standard deviation of 46.19. A simple random sample of 27 patients without heart disease is taken. The mean cholesterol level was 197.38 with a sample standard deviation of 24.09. Construct a 95% confidence interval. Round to the nearest hundredths.
  1. The following data on differences was obtained from a matched pair study.

4, 2, -3, 2, 1, 1, -4, -2, 0

Construct a 95% confidence interval. Round to the nearest hundredths. The standard deviation of the differences was 2.619.

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A special diet is intended to reduce the cholesterol of patients at risk of heart disease....
A special diet is intended to reduce the cholesterol of patients at risk of heart disease. If the diet is effective, the target is to have the average cholesterol of this group be below 200. After six months on the diet, an SRS of 150 patients at risk for heart disease had an average cholesterol level of 192 with a standard deviation of 21. Construct a 95% confidence interval for the average cholesterol level of patients at risk for heart...
A) In a study it was found out of a random sample of 41 these was...
A) In a study it was found out of a random sample of 41 these was a sample standard deviation of 3.6. Construct a 99% confidence interval for the populations standard deviation. What is the smaller value? [Round to the nearest hundredths place] B) What is the larger value? [Round to the nearest hundredths place]
Suppose that 200 researchers are interested in studying the sleeping habits of college freshmen. Each researcher...
Suppose that 200 researchers are interested in studying the sleeping habits of college freshmen. Each researcher takes a random sample of size 80 from the same population of freshmen. Each researcher is trying to estimate the mean hours of sleep that freshmen get at night, and each one constructs a 90% confidence interval for the mean. Approximately how many of these 200 confidence intervals will NOT capture the true mean? (You do not need to do any complicated computations here!)
Rudy Researcher is now interested in the drinking habits of students at the University of Alabama....
Rudy Researcher is now interested in the drinking habits of students at the University of Alabama. It is known that the average yearly consumptions of soft drinks by college students nationwide is 50 gallons (µ = 50) with a standard deviation of 3.5 gallons (σ = 3.5). To minimize costs, the Committee would like to reduce that 95% confidence interval to have a width of 0.5 gallons. What sample size would they need to collect in order to reduce their...
The mean age for all Foothill College students for a recent Fall term was 33.2. The...
The mean age for all Foothill College students for a recent Fall term was 33.2. The population standard deviation has been pretty consistent at 15. Suppose that twenty-five Winter students were randomly selected. The mean age for the sample was 30.4. We are interested in the true mean age for Winter Foothill College students. Let X = the age of a Winter Foothill College student. A. Construct a 95% Confidence Interval for the true mean age of Winter Foothill College...
Researchers are interested in the texting habits of all US adults. A random sample of n=755...
Researchers are interested in the texting habits of all US adults. A random sample of n=755 US cell phone users age 18 and older in May 2011 found that the average number of text messages sent or received per day is 41.5 messages, with standard error about 6.1. a)Because we did not take a census, we cannot give a specific value for the parameter, u. Instead, describe µ using words. Be very specific. b) What is our best estimate for...
We want to know the mean number of hours worked on a weekend day, among those...
We want to know the mean number of hours worked on a weekend day, among those who work weekends. Suppose that a simple random sample of size 1015 from the target population produced a sample mean of 5.2 hours. Further suppose that the sample standard deviation was 1.6. (a) What are the end points of a 90% confidence-interval estimate for the population mean? (Round to 2 digits after the decimal place.) [ , ] (b) What are the end points...
Find the following critical t-scores used in an 88% confidence interval for a population mean when...
Find the following critical t-scores used in an 88% confidence interval for a population mean when the population’s standard deviation (σσ) is unknown. Give each answer to at least three decimal places. The t-critical value for an 88% confidence interval with sample size 38 is: The t-critical value for an 88% confidence interval with sample size 48 is: The t-critical value for an 88% confidence interval with sample size 64 is: The t-critical value for an 88% confidence interval with...
According to the website www.collegedrinkingprevention.gov, “About 25 percent of college students report academic consequences of their...
According to the website www.collegedrinkingprevention.gov, “About 25 percent of college students report academic consequences of their drinking including missing class, falling behind, doing poorly on exams or papers, and receiving lower grades overall.” A statistics student is curious about drinking habits of students at his college. He wants to estimate the mean number of alcoholic drinks consumed each week by students at his college. He plans to use a 95% confidence interval. He surveys a random sample of 60 students....
The driving distances of college students who commute to a particular school are normally distributed. In...
The driving distances of college students who commute to a particular school are normally distributed. In a random sample of 8 college students, the sample mean driving distance was 22.2 miles and the sample standard deviation was 5.8 miles. (a). Construct a 98% confidence interval for the mean driving distance of all the college students who drive to the school. Write a sentence interpreting your interval. (Round answer to 2 decimal places) 7(b). Suppose the population standard deviation was known...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT