Question

For each of the following situations give the degrees of freedom and an appropriate bound on the P-value (give the exact value if you have software available) for the χ² statistic for testing the null hypothesis of no association between the row and column variables.

(a) A 2 by 2 table with χ² = 1.09.

df =
P-value =

(b) A 4 by 4 table with χ² = 18.78.

df =
P-value =

(c) A 2 by 8 table with χ² = 24.18.

df =
P-value =

(d) A 5 by 3 table with χ² = 12.59.

df =
P-value =

Answer 1

(a) A 2 by 2 table with χ2 = 1.09.

df =1  
P-value =0.2965   ...................by using Excel command CHIDIST(1.09,1)  

(b) A 4 by 4 table with χ2 = 18.78.

df =9  
P-value =0.0271   ...................by using Excel command CHIDIST(18.78,9)  

(c) A 2 by 8 table with χ2 = 24.18.

df =7  
P-value =0.0011   ...................by using Excel command CHIDIST(24.18,7)  

(d) A 5 by 3 table with χ2 = 12.59.

df =8  
P-value =0.1268....................by using Excel command CHIDIST(12.59,8)