Question

How many words (both nonsense and sensical) may be formed using all the letters of the word SENSELESS where N and L are the first and last letters. (i.e. Case 1: N _ _ _ L and Case 2: L _ _ _ _ N)

The choices given are:

1. 70
2. 35
3. 840
4. 1260
5. 1960

Answer 1

There are 9 letters in the word SENSELESS,

The letter S is appears 4 times and

Letter E appears 3 times

So in CASE 1, with N first and L last letter

We have number of words possible is

As there are 7 letters 4 S's and 3 E's

In similar way the number of words possible with L first and N last is

As there are 7 letters 4 S's and 3 E's

Hence the total number of words possible is

Option a) is correct