2) Kudzu is a plant that was imported to the United States from Japan and now covers over seven million acres in the South. The plant contains chemicals called isoflavones that have been shown to have beneficial effects on bone mineral density. a) State the Hypothesis to show isoflavones have beneficial effects on bone mineral density. b) Choose a level of significance Use a = 0.05 for this problem. c) To test the hypothesis, a study used three groups of rats to compare a control group with rats that were fed either a low dose or a high dose of isoflavones from kudzu. At the end of the study period the researchers measured the bone mineral density in the femur (in grams per square centimeter). The data appear in the Kudzu worksheet of the HW4 data workbook on Moodle. Test the hypothesis using Excel. d) Draw a conclusion and report that in the context of the problem. e) Use Fisher’s LSD Test with a = 0.05 to determine which, if any, levels of dosage give significantly different densities. f) Assume that dosage is a random factor, i.e., the dosage levels represent a random sample of all possible dosage levels. Estimate the components of variance in bone density
data:
Control | Low dose | High dose |
0.228 | 0.221 | 0.25 |
0.207 | 0.22 | 0.237 |
0.234 | 0.211 | 0.217 |
0.22 | 0.233 | 0.206 |
0.217 | 0.219 | 0.247 |
0.228 | 0.233 | 0.228 |
0.209 | 0.226 | 0.245 |
0.221 | 0.228 | 0.232 |
0.204 | 0.216 | 0.267 |
0.22 | 0.225 | 0.261 |
0.203 | 0.2 | 0.221 |
0.219 | 0.208 | 0.219 |
0.218 | 0.198 | 0.232 |
0.245 | 0.208 | 0.209 |
0.21 | 0.203 | 0.255 |
a)
b)
alpha = 0.05 is chosen
c)
anova single factor
Anova: Single Factor | ||||||
SUMMARY | ||||||
Groups | Count | Sum | Average | Variance | ||
Control | 15 | 3.283 | 0.218866667 | 0.000134267 | ||
Low dose | 15 | 3.249 | 0.2166 | 0.000132114 | ||
High dose | 15 | 3.526 | 0.235066667 | 0.000352352 | ||
ANOVA | ||||||
Source of Variation | SS | df | MS | F | P-value | F crit |
Between Groups | 0.003042978 | 2 | 0.001521489 | 7.377114535 | 0.001795859 | 3.219942293 |
Within Groups | 0.008662267 | 42 | 0.000206244 | |||
Total | 0.011705244 | 44 |
d)
p-value = 0.00179
p-value < 0.05
hence we reject the null hypothesis
we conclude that
isoflavones have beneficial effects on bone mineral density
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