Question

A container contains

15

diesel engines. The company chooses

4

engines at​ random, and will not ship the container if any of the engines chosen are defective. Find the probability that a container will be shipped even though it contains 2 defective engines.

Answer 1

Total probability of defective engine = 2/15

Hence p= 2/15

and q=1-p =13/15

We need to use binomial theorem to find the probability of rejecting

P(X=0 defective from n=4) = ?

P(X=0) = nCr * p^x * q^(n-x)

P(X=0) = 4C0 * (2/15)^0 * (13/15)^4 =0.5642

Hence we can say that 0.5642 is the probability of a container will be shipped even though it contains 2 defective engines.

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