A lot contains 12 items and 4 are defective. If two items are drawn at random from the lot, without replacement, what is the probability there is exactly one defective?
Number of items in the lot = 12
Number of defective items of the lot =4
Number of items drawn from the lot =2
Number of ways drawing 2 items from 12 items =
Number of ways of drawing 1 defective item from 4 defective items =
Number of ways of drawing 1 non defective item from 8 non defective items =
Probability there is exactly one defective =
(Number of ways of drawing 1 defective item from 4 defective items x Number of ways of drawing 1 non defective item from 8 non defective items) / Number of ways drawing 2 items from 12 items
= (4x8)/66 = 32/66 = 16/33 = 0.4848
Probability there is exactly one defective = 0.4848
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