Prove that conditional independence is symmetric (i.e. if A is independent of B given C then B is independent of A given C).
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Given, A is independent of B given C.
i.e., P(A|B, C) = P(A|C)----------------(1)
Now, P(B|A, C) = P(BA|C) / P(A|C)--------------(2)
From equation (1), using the value of P(A|C) into equation (2), we get-
P(B|A, C) = P(BA|C) / P(A|B, C)
P(B|A, C)*P(A|B, C) = P(BA|C)-----------(3)
From (3),
B is independent of A given C. ( If two events E and F are independent then P(E)*P(F) = P(EE) )
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