Question

Please compute the following: a) P(Z > 1.26), . P(Z < −0.86), P(Z > −1.37), P(−1.25...

Please compute the following:
a) P(Z > 1.26), . P(Z < −0.86), P(Z > −1.37), P(−1.25 < Z < 0.37), . P(Z ≤ −4.6)
b) Find the value ? such that ?(? > ?) = 0.05
c) Find the value of ? such that ?(−? < ? < ?) = 0.99

Homework Answers

Answer #1

Please don't hesitate to give a "thumbs up" for the answer in case the answer has helped you

We make use of the Z tables wherever possible to convert Z to cumulative probabilty or vice-versa.

All answers are rounded to 4 decimal places. All answers are highligted in bold.

a) .

i) P(Z > 1.26)

= 1 - P(Z < 1.26)

= 1- 0.8962

= 0.1038

ii) P(Z < −0.86),

= 0.1949

iii) P(Z > −1.37)

= 1 - P(Z < -1.37)

= 1 - 0.0853

= 0.9147

iv)

P(−1.25 < Z < 0.37) =

= P(Z<.37) - P(Z<-1.25)

= .6443 - .1056

= 0.5387

v)

P(Z ≤ −4.6)

= 0.0000


b) Find the value ? such that ?(? > ?) = 0.05

P(Z>z) = 1-P(Z<z) = .05

P(Z<z) = .95

z = 1.6449

c)

Find the value of ? such that ?(−? < ? < ?) = 0.99

This can be expressed as :

2*P(-z<Z) = 1-.99

P(-z<Z) =(1- .99)/2 = (.01)/2 = .005

-z = -2.5758 or

z = 2.5758

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Find the following probabilities. (Round your answers to four decimal places.) (a)    p(0 < z < 1.63)...
Find the following probabilities. (Round your answers to four decimal places.) (a)    p(0 < z < 1.63) (b)    p(1.30 < z < 1.86) (c)    p(−0.37 < z < 1.59) (d)    p(z < −1.93) (e)    p(−1.33 < z < −0.86) (f)    p(z < 1.25)
Find the P-value for Z > 1.25 & Find the P-value for -1.24 < z <...
Find the P-value for Z > 1.25 & Find the P-value for -1.24 < z < 2.20
The alternative hypothesis is H1: p < 0.15, and the test statistic is z= -1.37 ....
The alternative hypothesis is H1: p < 0.15, and the test statistic is z= -1.37 . Find p-value of the large sample one proportion z-test. Find critical value t a/2 for a one sample t test to test H1: μ   ≠ 5 at a significance level a=0.05 and degrees freedom = 15. A company wants to determine if the average shearing strength of all rivets manufactured is more than 1000 lbs. A sample of 25 rivets is selected and tested...
-. For what follows, Z denotes the standard normal random variable. (1) P(Z<1.26) is about (a)...
-. For what follows, Z denotes the standard normal random variable. (1) P(Z<1.26) is about (a) 0.7924 (b) 0.3962 (c) 0.1038 (d) 0.6038 (e) 0.8962 (2) P(-0.54 < Z < 0.78) is about (a) 0.2054 (b) 0.0769 (c) 0.4877 (d) 0.2823 (e) 0.6877 -Assume the random variable X is normally distributed with mean 172 and standard deviation 10. Find the following probabilities. (3) P(X<160) (a) 0.8849 (b) 0.1151 (c) 0.9999 (d) 0.8078 (e) 0.8438 (4) P(X>150) (a) 0.0139 (b) 0.9861...
Given that z is a standard normal random variable, use the Excel to compute the following...
Given that z is a standard normal random variable, use the Excel to compute the following probabilities. a) P(z > 0.5) b) P(z ≤ −1) c) P(1≤ Z ≤ 1.5) d) P(0.5 ≤ z ≤ 1.25) e) P(0 < z < 2.5)
Show work please. Compute z-scores or t-scores accordingly then find their one-tailed AND two-tailed p-value the...
Show work please. Compute z-scores or t-scores accordingly then find their one-tailed AND two-tailed p-value the following situations. Then, summarize the results of the analysis at α level 0.05. The sample mean consumption of 16 Missouri men is 2610 kcal, with an estimated standard error of 175 kcal. Test the hypothesis that the mean is greater than the population mean consumption of US men of 2350.
Find the following probabilities. (Round your answers to four decimal places.) (a) p(0 < z <...
Find the following probabilities. (Round your answers to four decimal places.) (a) p(0 < z < 1.62) (b) p(1.40 < z < 1.83) (c) p(−0.38 < z < 1.55) (d) p(z < −1.91) (e) p(−1.32 < z < −0.86) (f) p(z < 1.27)
Z is a standard normal random variable. Compute the following probabilities. a. P(-1.33 Z 1.67) b....
Z is a standard normal random variable. Compute the following probabilities. a. P(-1.33 Z 1.67) b. P(1.23 Z 1.55) c. P(Z 2.32) d. P(Z -2.08) e. P(Z -1.08)
Find the area under the standard normal curve between: (a) P(-1.5<z<1.25) (b) to the right of...
Find the area under the standard normal curve between: (a) P(-1.5<z<1.25) (b) to the right of z=1.06 P(z<-2.58 or z>2.58)
Show work please. Compute z-scores or t-scores accordingly then find their one-tailed AND two-tailed p-value the...
Show work please. Compute z-scores or t-scores accordingly then find their one-tailed AND two-tailed p-value the following situations. Then, summarize the results of the analysis at α level 0.05. The mean BMI of US men is 26 with the population standard deviation of 4. You have data from a sample of 25 US men with type II diabetes, who are attending a diabetes health promotion program. The mean BMI of the sample is 28.34.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT