Random samples of female and male UVA undergraduates are asked to estimate the number of alcoholic drinks that each consumes on a typical weekend. The data is below:
Females (Population 1): 3, 2, 4, 3, 4, 1, 3, 2, 3, 0
Males (Population 2): 6, 8, 6, 5, 7, 8, 6, 5, 6, 6
Give a 92.9% confidence interval for the difference between mean female and male drink consumption. (Assume that the population variances are equal.)
Confidence Interval =
Here we want to find a 92.9% confidence interval for the difference between mean female and male drink consumption. Also we are assume that the population variances are equal.
Let's use Minitab:
First enter the given datasets in minitab columns:
Steps 1) Click on Stat>>>Basic Statistics>>>2-Sample t...
Steps 1) Click on Sample in different columns
look the following picture.
step 3) Click on Option
look the following picture.
then click on OK again click on OK
So we get the following output
From the above output the 92.9% confidence interval is
Confidence Interval = (-4.803, -2.797)
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