Question

# Random samples of female and male UVA undergraduates are asked to estimate the number of alcoholic...

Random samples of female and male UVA undergraduates are asked to estimate the number of alcoholic drinks that each consumes on a typical weekend. The data is below: Females (Population 1): 2, 4, 4, 5, 4, 3, 5, 4, 2, 2 Males (Population 2): 8, 9, 6, 9, 9, 5, 5, 7, 8, 8 Give a 91.6% confidence interval for the difference between mean female and male drink consumption. (Assume that the population variances are equal.) Confidence Interval =

Ans:

df=10+10-2=18

t*=TINV(0.084,18)=1.829

 Females Males 1 2 8 2 4 9 3 4 6 4 5 9 5 4 9 6 3 5 7 5 5 8 4 7 9 2 8 10 2 8 mean 3.5 7.4 std. dev. 1.1785 1.5776

Point estimate=3.5-7.4=-3.9

standard error for difference=sqrt((1.1785^2/10)+(1.5776^2/10))=0.6227

91.6% confidence interval for the difference between mean female and male drink consumption

=-3.9+/-1.829*0.6227

=-3.9+/-1.139

=(-5.039, -2.761)

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