Question

In a clinical trial, 17 out of 863 patients taking a prescription drug daily complained of flulike symptoms. Suppose that it is known that 1.6% of patients taking competing drugs complain of flulike symptoms. Is there sufficient evidence to conclude that more than 1.6% of this drug's users experience flulike symptoms as a side effect at the α=0.1 level of significance?

Because np (01−p0) =__?__

▼

>

=

<

≠

10, the sample size is

▼

less than

greater than

5% of the population size, and the sample

▼

is given to not be random,

is given to be random,

cannot be reasonably assumed to be random,

can be reasonably assumed to be random,

the requirements for testing the hypothesis

▼

are

are not

satisfied.

(Round to one decimal place as needed.)

Answer #1

p_{0} = 1.6% = 0.016

np_{0} (1-p_{0}) = 863 * 0.016 * (1- 0.016) =
13.587

Because, np_{0} (1-p_{0}) > 10

the sample size is less than 5% of the population size, and the sample

can be reasonably assumed to be random

the requirements for testing the hypothesis

are satisfied.

H0: p_{0} = 0.016

H1: p_{0} > 0.016

Standard error of proportion = = 0.00427

Sample proportion, p = 17/863 = 0.0197

Test statistic, z = (p - p_{0}) / Std error

= (0.0197 - 0.016) / 0.00427

= 0.8665

P-value = P(z > 0.8665) = 0.1931

Since, p-value is greater than 0.01 significance level, we fail to reject null hypothesis H0 and there is no sufficient evidence to conclude that more than 1.6% of this drug's users experience flulike symptoms as a side effect

In a clinical trial,
18
out of
884
patients taking a prescription drug daily complained of flulike
symptoms. Suppose that it is known that1.6%
of patients taking competing drugs complain of flulike symptoms.
Is there sufficient evidence to conclude that more than
1.6%
of this drug's users experience flulike symptoms as a side
effect at the
alpha equals 0.1α=0.1
level of significance?
Because np 0 left parenthesis 1 minus p 0 right
parenthesisnp01−p0equals=nothing
▼
equals=
not equals≠
less than<
greater...

In a clinical trial, 23 out of 898 patients taking a
prescription drug daily complained of flulike symptoms. Suppose
that it is known that 2.3% of patients taking competing drugs
complain of flulike symptoms. Is there sufficient evidence to
conclude that more than 2.3% of this drug's users experience
flulike symptoms as a side effect at the alpha equals 0.05 level
of significance? Because np 0 left parenthesis 1 minus p 0 right
parenthesisequals 18 greater than 10, the sample...

In a clinical trial, 20 out of 881 patients taking a
prescription drug daily complained of flulike symptoms. Suppose
that it is known that 1.9% of patients taking competing drugs
complain of flulike symptoms. Is there sufficient evidence to
conclude that more than 1.9% of this drug's users experience
flulike symptoms as a side effect at the α=0.05 level of
significance?
Because np 0 (1 minus p 0) = 10, the sample size is ▼ less than
or greater than...

In a clinical trial, 16 out of 870 patients taking a
prescription drug daily complained of flulike symptoms. Suppose
that it is known that 1.6% of patients taking competing drugs
complain of flulike symptoms. Is there sufficient evidence to
conclude that more than 1.6% of this drug's users experience
flulike symptoms as a side effect at the equals α=0.05 level of
significance?

In a clinical trial, 19 out of 859 patients taking a
prescription drug daily complained of flulike symptoms. Suppose
that it is known that 1.8% of patients taking competing drugs
complain of flulike symptoms. Is there sufficient evidence to
conclude that more than 1.8% of this drug's users experience
flulike symptoms as a side effect at the alpha equals 0.1 level of
significance?

In a clinical trial, 27 out of 867 patients taking a
prescription drug daily complained of flulike symptoms. Suppose
that it is known that 2.8% of patients taking competing drugs
complain of flulike symptoms. Is there sufficient evidence to
conclude that more than 2.8% of this drug's users experience
flulike symptoms as a side effect at the α=0.05 level of
significance?

In a clinical trial, 18 out of 868 patients taking a
prescription drug daily complained of flulike symptoms. Suppose
that it is known that 1.7% of patients taking competing drugs
complain of flulike symptoms. Is there sufficient evidence to
conclude that more than 1.7% of this drug's users experience
flulike symptoms as a side effect at the α=0.01 level of
significance?
Because np 0 (1 minus p 0) = ▼ < ≠ > = 10, the sample size
is ▼...

in a clinical trial, 22 out of 829 patients taking a
prescription drug daily complained of flu like symptoms. Suppose
that it is known that 2.3% of patients taking competing drugs
complain of flulike symptoms. Is there sufficient evidence to
conclude that more than 2.3% of this drug's users experience
flulike symptoms as a side effect at the alpha equals 0.01 level
of significance?

In a clinical trial, 27 out of 876patients taking a
prescription drug daily complained of flulike symptoms. Suppose
that it is known that 2.8% of patients taking competing drugs
complain of flulike symptoms. Is there sufficient evidence to
conclude that more than 2.8% of this drug's users experience
flulike symptoms as a side effect at the alpha equals α=0.01level
of significance?

In a clinical trial, 28 out of 878 patients taking a
prescription drug daily complained of flulike symptoms. Suppose
that it is known that 2.7% of patients taking competing drugs
complain of flulike symptoms. Is there sufficient evidence to
conclude that more than 2.7% of this drug's users experience
flulike symptoms as a side effect at the alpha equals 0.1 level of
significance? Because np 0 left parenthesis 1 minus p 0 right
parenthesisequals nothing ▼ 10, the sample size...

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 13 minutes ago

asked 32 minutes ago

asked 45 minutes ago

asked 45 minutes ago

asked 49 minutes ago

asked 55 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 2 hours ago

asked 2 hours ago

asked 3 hours ago

asked 3 hours ago