Question

In a clinical​ trial, 16 out of 870 patients taking a prescription drug daily complained of flulike symptoms. Suppose that it is known that 1.6​% of patients taking competing drugs complain of flulike symptoms. Is there sufficient evidence to conclude that more than 1.6​% of this​ drug's users experience flulike symptoms as a side effect at the equals α=0.05 level of​ significance?

Answer 1

Solution :

This is the right tailed test .

The null and alternative hypothesis is

H₀ : p = 0.016

H_a : p > 0.016

= x / n = 16 / 870 = 0.0184

Test statistic = z

= - P₀ / [P_{0 *} (1 - P₀ ) / n]

= 0.0184 - 0.016 / [(0.016 * 0.984) / 870]

= 0.562

P-value = 0.2871

= 0.05

P-value >

Fail to reject the null hypothesis .

There is not sufficient evidence to suggest that  more than 1.6​% of this​ drug's users experience flulike symptoms as a side effect at the equals α=0.05 level of​significance