The director of research and development is testing a new drug. She wants to know if there is evidence at the 0.1 level that the drug stays in the system for more than 363 minutes. For a sample of 19 patients, the mean time the drug stayed in the system was 373 minutes with a variance of 576. Assume the population distribution is approximately normal.
Step 1 of 3: State the null and alternative hypotheses.
Step 2 of 3: Find the P-value for the hypothesis test. Round your answer to four decimal places.
Step 3 of 3: Make the decision to reject or fail to reject the null hypothesis.
Solution :
Given that,
= 373
s = 24
n = 19
a.) Hypothesis:
H0 : 363
Ha : 363
Test Statistic:
t = ( - ) / (s /n)
t = (373 - 363) / ( 24 / 19 )
t = 1.816
P - value = 0.0430
if P- value < 0.1 then reject H0.
P-value < 0.1, we reject H0.
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