The director of research and development is testing a new drug. She wants to know if there is evidence at the 0.1 level that the drug stays in the system for more than 367 minutes. For a sample of 46 patients, the mean time the drug stayed in the system was 373 minutes. Assume the population standard deviation is 24. Find the P-value of the test statistic.
Solution :
The null and alternative hypothesis is ,
H0 : = 367
Ha : 367
Test statistic = z
= ( - ) / / n
= (373 - 367) / 24 / 46
Test statistic = 1.70
P-value = 0.0450
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