The number of chocolate chips in an 18-ounce bag of chocolate chip cookies is approximately normally distributed with a mean of 1252 chips and standard deviation 129 chips.
(a) What is the probability that a randomly selected bag contains between 1100 and 1500 chocolate chips, inclusive?
(b) What is the probability that a randomly selected bag contains fewer than 1050 chocolate chips?
(c) What proportion of bags contains more than 1200 chocolate chips?
(d) What is the percentile rank of a bag that contains 1475 chocolate chips?
solution:-
given that mean = 1252 chips and standard deviation = 129 chips
(a) P(1100 < x < 1500)
=> P((1100-1252)/129 < z < (1500-1252)/129)
=> P(-1.18 < z < 1.92)
=> P(z < 1.92) - P(z < -1.18)
=> 0.9726 - 0.1190
=> 0.8536
(b) P(x < 1050)
=> P(z < (1050-1252)/129)
=> P(z < -1.57)
=> 1 - P(z < 1.57)
=> 1 - 0.9418
=> 0.0582
(c) P(x > 1200)
=> P(z > (1200-1252)/129)
=> P(z > -0.40)
=> P(z < 0.40)
=> 0.6554
(d) the percentile rank of a bag that contains 1475 chocolate
chips
=> P(X < 1475)
=> P(z < (1475-1252)/129)
=> P(z < 1.73)
=> 0.9582
=> 96 percentile
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