Question

XYZ College is planning for the next commencement and has the following estimates to work with. There are 409 students/hr on average going through the commencement process. The school wishes to complete the commencement exercise within an hour. An average of 12 students are hooded per minute. Names are called @ one student every 7 seconds. The walk to go to the center of the stage, and physically receive the diploma, takes a student 8.2 seconds, on average. It takes an additional 2 seconds for a student to walk on and exit the stage. There are 5 students on stage, on average - some being hooded, some waiting for their names to be called, some walking to receive their diplomas, and some exiting the stage. What is the average Flow TIme of a student through the entire process? (Pick the closest answer). Hint: Use Little's law. Avg. Inv = Avg Flow Rate x Avg Flow TIme

Answer 1

Time for Calling of names = 7

Time for Walking and receiving diploma = 8.2

Time for a student to walk and exit =2

Throughput time of the system ( T) = Time for Calling of names + Time for Walking and receiving diploma + Time for a student to walk and exit

T = 7 + 8.2 + 2

T = 17.2 seconds

Inventory of the student (I), i.e. number of students on stage = 5

As per Little’s Law,

Inventory in the system = Rate of flow in the system x Throughput time of the system

Let , average flow time of students = R seconds

Then,

R X T = I

R X 17.2 = 5

Or, R =5 / 17.2 = 0.291

Therefore, Average flowtime per student = 0.291 /second

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