Question

Sixty three percent of adults’ trust newspapers to present news fairly. You randomly select 9 adults....

Sixty three percent of adults’ trust newspapers to present news fairly. You randomly select 9 adults. Find the probability that the number of adults who trust newspapers to present the news fairly is exactly 5. (Do not round values and show all work)

Homework Answers

Answer #1

Probability calculation by binomial probability distribution formula.

Here probability of who trust newspapers to present the news fairly is exactly 5 is 0.2343

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
61​% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults....
61​% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that the number of U.S. adults who have very little confidence in newspapers is ​ (a) exactly​ five, (b) at least​ six, and​ (c) less than four. ​(a) ​P(5) = ? ​(Round to three decimal places as​ needed.)​ (b) ​P(x≥​6) = ? ​(Round to three decimal places as​ needed.)​ (c) ​P(x<​4) = ? ​(Round to three decimal places as​ needed.)
Thirty percent of adults strongly believe the news from social media. You randomly select five adults....
Thirty percent of adults strongly believe the news from social media. You randomly select five adults. Find the probability that the number of adults who strongly believe the news from social media is less than three. Group of answer choices 0.132 0.163 0.837 0.969 Thirty percent of adults strongly believe the news from social media. You randomly select ten adults. Find the probability that the number of adults who strongly believe the news from social media is at most seven....
59​% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults....
59​% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that the number of U.S. adults who have very little confidence in newspapers is ​ (a) exactly​ five, (b) at least​ six, and​ (c) less than four.
66​% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults....
66​% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that the number of U.S. adults who have very little confidence in newspapers is ​ (a) exactly​ five, (b) at least​ six, and​ (c) less than four.
47​% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults....
47​% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that the number of U.S. adults who have very little confidence in newspapers is ​ (a) exactly​ five, (b) at least​ six, and​ (c) less than four. ​
In a typical day, 61% of U.S. adults go online to get news. You randomly select...
In a typical day, 61% of U.S. adults go online to get news. You randomly select five U.S. adults. Find the probability that the number of U.S. adults who say they go online to get news is a) Exactly 2. b)At least two. c)More than two
sixty percent of consumers prefer to purchase electronics online. You randomly select 8 consumers. Find the...
sixty percent of consumers prefer to purchase electronics online. You randomly select 8 consumers. Find the probability that the number of consumers who prefer to purchase electronics online is​ (a) exactly​ five, (b) more than​ five, and​ (c) at most five.
56% of us adults have very little confidence in newspaper. you randomly select 10 us adults....
56% of us adults have very little confidence in newspaper. you randomly select 10 us adults. find the probability that the number of us adults who have very little confidence in newspaper is exactly five at least six and less than four. a P(5) round to 3 decimal place
Sixty-nine percent of US college graduates expect to stay at their first employer for three or...
Sixty-nine percent of US college graduates expect to stay at their first employer for three or more years. You randomly select 18 US college graduates and ask them whether they expect to stay at their first employer for 3 or more years. Find the probability that the number who expect to stay at their employer for three or more years is (a) Exactly six people (b) Less than 7 and (c) at least 15. Identify any unusual events Explain
Based on a? poll, 40?% of adults believe in reincarnation. Assume that 7 adults are randomly?...
Based on a? poll, 40?% of adults believe in reincarnation. Assume that 7 adults are randomly? selected, and find the indicated probability. Complete parts? (a) through? (d) below. a. What is the probability that exactly 6 of the selected adults believe in? reincarnation? The probability that exactly 6 of the 7 adults believe in reincarnation is nothing. ?(Round to three decimal places as? needed.) b. What is the probability that all of the selected adults believe in? reincarnation? The probability...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT