59% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that the number of U.S. adults who have very little confidence in newspapers is (a) exactly five, (b) at least six, and (c) less than four.
Proportion of adults that have very little confidence in newspaper, p = 0.59
Sample size, n = 10
X~ Binomial(10, 0.59)
a) Probability that exactly 5 have very little confidence, P(X =5) =
Using binomial function in excel:
=BINOM.DIST(5, 10, 0.59, 0)
= 0.2087
b) Probability that at least 6 have very little confidence, P(X >= 6) = 1-P(X<6)
= 1-P(X<=5)
Using binomial function in excel:
= 1 - BINOM.DIST(5, 10, 0.59, 1)
= 1 - 0.3922 = 0.6078
c) Probability that less than 4 have very little confidence, P(X < 4) = P(X <= 3)
= P(X<= 3)
Using binomial function in excel:
= BINOM.DIST(3, 10, 0.59, 1)
= 0.0626
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