Question

Each person in random samples of 207 male and 283 female working adults living in a certain town in Canada was asked how long, in minutes, his or her typical daily commute was. (Use a statistical computer package to calculate the P-value. Use ?_males ? ?_females. Round your test statistic to two decimal places, your df down to the nearest whole number, and your P-value to three decimal places.)

Males			Females
Sample size	x	s	Sample size	x	s
207	31.6	24.0	283	29.3	24.3

df?

t?

p value?

2

Do female college students spend more time than male college students watching TV? This was one of the questions investigated by the authors of an article. Each student in a random sample of 46 male students at a university in England and each student in a random sample of 38 female students from the same university kept a diary of how he or she spent time over a three-week period.

For the sample of males, the mean time spent watching TV per day was 68.8 minutes and the standard deviation was 67.5 minutes. For the sample of females, the mean time spent watching TV per day was 93.9 minutes and the standard deviation was 89.1 minutes. Is there convincing evidence that the mean time female students at this university spend watching TV is greater than the mean time for male students? Test the appropriate hypotheses using

? = 0.05.

(Use a statistical computer package to calculate the P-value. Use ?_males ? ?_females.Round your test statistic to two decimal places, your df down to the nearest whole number, and your P-value to three decimal places.)

t	=
df	=
P-value	=

Answer 1

1:

Here we have following information:

Here hypotheses are:

Pooled standard deviation is :

and t-statistics will be

Here degree of feedom will be

The p-value is: 0.2987

Since p-value is greater than 0.01 so we fail to reject the null hypothesis.