Consider a normal distribution curve where 90-th percentile is at 17 and the 40-th percentile is at 8. Use this information to find the mean, μ , and the standard deviation, σ , of the distribution.
a) μ=
b) σ=
Solution:
The critical Z value for 90th percentile by using z-table is given as Z = 1.281552
The critical Z value for 40th percentile by using z-table is given as Z = -0.25335
X = µ + Z*σ
So, from given information, we have
µ + 1.281552*σ = 17
µ - 0.25335*σ = 8
Subtract equation 2 from equation 1, we get
1.534899*σ = 17 - 8 = 9
σ = 9/1.534899
σ = 5.863578
µ + 1.281552*σ = 17
µ + 1.281552*5.863578 = 17
µ + 7.51448 = 17
µ = 17 - 7.51448
µ = 9.48552
a) μ=9.48552
b) σ= 5.863578
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