Consider a normal distribution curve where the middle 35 % of the area under the curve lies above the interval ( 3 , 11 ). Use this information to find the mean, μ and the standard deviation, σ of the distribution.
Solution:
P(3<X<11) = 0.35
P(X<3) = (1 - 0.35)/2 = 0.325
Z = (X - mean)/SD
-0.45376 = (3 - mean)/SD
(by using z-table)
-0.45376*SD = (3 - mean)
Mean - 0.45376*SD = 3
(equation 1)
Now, we have
P(X>11) = (1 - 0.35)/2 = 0.325
Z = (X - mean)/SD
0.45376 = (11 - mean)/SD
0.45376*SD = (11 - mean)
Mean + 0.45376*SD = 11
(equation 2)
Now, solve equation 1 and 2 for the values of mean and SD.
By adding equation 1 and 2, we get
Mean - 0.45376*SD = 3
Mean + 0.45376*SD = 11
===========================
2*Mean = 14
Mean = 14/2 = 7
Mean = 7
Mean - 0.45376*SD = 3
7 - 0.45376*SD = 3
0.45376*SD = 7 - 3 = 4
SD = 4/0.45376 = 8.815233
SD = 8.815233
μ = 7
σ = 8.82
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