Question

A) About 6% of the population has a particular genetic mutation. 1000 people are randomly selected. Find the mean for the number of people with the genetic mutation in such groups of 1000. (Round 2 decimal places if possible.)

B) About 7% of the population has a particular genetic mutation. 100 people are randomly selected. Find the standard deviation for the number of people with the genetic mutation in such groups of 100. (If possible round to 1 decimal place.).

Answer 1

A) Given : n=1000 , p=0.06

Let , X be the number of people with the genetic mutation.

Here , X has binomial distribution with paramater n=1000 and 0.06

Therefore , the mean for the number of people with the genetic mutation in such groups of 1000 is ,

mean=np=1000*0.06=60

B)

Given : n=100 , p=0.07

Let , X be the number of people with the genetic mutation.

Here , X has binomial distribution with paramater n=100 and 0.07

Therefore , the standard deviation for the number of people with the genetic mutation in such groups of 100 is ,