Question

About 2% of the population has a particular genetic mutation. 800 people are randomly selected.

Find the mean for the number of people with the genetic mutation in such groups of 800.



Find the standard deviation for the number of people with the genetic mutation in such groups of 800. Round your answer to 4 decimal places.

Answer 1

Solution:

Given,

p = 2% = 0.02

q = 1 - p = 1 - 0.02 = 0.98

n = 800

Let X be the number of  people with the genetic mutation in such groups of 800.

  X follows the Binomial(800 , 0.02)

a)

Mean = n*p = 800 * 0.02 = 16

Mean = 16

b)

Standard deviation = =   =   =  3.9598

Standard deviation =  3.9598