Question

About 8% of the population has a particular genetic mutation. 500 people are randomly selected.

Find the standard deviation for the number of people with the genetic mutation in such groups of 500.

   

Answer 1

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This problem demands the application of binomial distribution, where in we have been given the sample size (n) and the probability of event sucess (p)

Hence, given X is an event defined in the following way, we will write the binomial distribution as : B(n,p) = B(500, 0.08)

Let X be a random variable denoting the number of people having genetic mutation out of 300 people. X follows binomial distribution as mentioned above.

The standard deviation of X is given by the formula :
= sqrt(n*p*(1-p))

= sqrt(500*0.08*(1-0.08)) = 6.0663

Answer: 6.0663