Suppose the probability that a lightbulb is defective is 0.1.
What is the probability that if you select a random sample of 8 lightbulbs, exactly 2 of the 8 lightbulbs will be defective?
I know what the answer should be please explain how you got to it
Solution:
We are given that: the probability that a lightbulb is defective is 0.1
Thus p = probability that a lightbulb is defective = 0.1
We have to find the probability that if you select a random sample of 8 lightbulbs, exactly 2 of the 8 lightbulbs will be defective.
That is we have to find: P( X = 2) = ..........?
n =sample size = 8
X = number of defective lightbulbs follows Binomial distribution with n = 8 and p = 0.1
Thus using Binomial probability distribution:
where
and q = 1 - p = 1 - 0.1 = 0.9
Thus
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