Question

Suppose a shipment of 400 components contains 68 defective and 332 non-defective computer components. From the...

Suppose a shipment of 400 components contains 68 defective and 332 non-defective computer components. From the shipment you take a random sample of 25. When sampling with replacement (so that the p = probability of success does not change), note that a success in this case is selecting a defective part. In our sample of 25 we reject the entire shipment if X>5. What is the probability of rejecting the entire shipment?

Homework Answers

Answer #1

p = 68 / 400 = 0.17

n = 25

This is a binomial distribution.

P(X = x) = 25Cx * 0.17x * (1 - 0.17)25-x

P(X > 5) = 1 - (P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5))

               = 1 - (25C0 * 0.170 * 0.8325 + 25C1 * 0.171 * 0.8324 + 25C2 * 0.172 * 0.8323 + 25C3 * 0.173 * 0.8322 + 25C4 * 0.174 * 0.8321 + 25C5 * 0.175 * 0.8320 )

             = 1 - 0.7575

             = 0.2425

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