Question

The number of pizzas consumed per month by university students is normally distributed with a mean...

The number of pizzas consumed per month by university students is normally distributed with a mean of 7 and a standard deviation of 4.

A. What proportion of students consume more than 9 pizzas per month?

Probability =

B. What is the probability that in a random sample of size 9, the mean amount of pizza consumed is more than 5 pizzas per person?

Probability =

Homework Answers

Answer #1

Solution :

A.

P(x > 9) = 1 - P(x < 9)

= 1 - P[(x - ) / < (9 - 7) / 4)

= 1 - P(z < 0.5)

= 1 - 0.6915

= 0.3085

Probability = 0.3085

B.

= / n = 4 / 9 = 1.3333

P( > 5) = 1 - P( < 5)

= 1 - P[( - ) / < (5 - 7) / 1.3333]

= 1 - P(z < -1.50)

= 1 - 0.0668

= 0.9332

Probability = 0.9332

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The number of pizzas consumed per month by university students is normally distributed with a mean...
The number of pizzas consumed per month by university students is normally distributed with a mean of 9 and a standard deviation of 5. A. What proportion of students consume more than 12 pizzas per month? Probability = B. What is the probability that in a random sample of size 10, a total of more than 110 pizzas are consumed? (Hint: What is the mean number of pizzas consumed by the sample of 10 students?) Probability =
A survey of high school students revealed that the number of soft drinks consumed per month...
A survey of high school students revealed that the number of soft drinks consumed per month was normally distributed with a mean of 25 and standard deviation 15. A sample of 36 students was selected. What is the probability that the average number of soft drinks consumed per month for the sample was between 28.7 and 30 soft drinks
The amount of calories consumed by customers at the Chinese buffet is normally distributed with mean...
The amount of calories consumed by customers at the Chinese buffet is normally distributed with mean 2608 and standard deviation 517. One randomly selected customer is observed to see how many calories X that customer consumes. Round all answers to 4 decimal places where possible. a. What is the distribution of X? X ~ N(,) b. Find the probability that the customer consumes less than 2332 calories. c. What proportion of the customers consume over 2828 calories? d. The Piggy...
The amount of calories consumed by customers at the Chinese buffet is normally distributed with mean...
The amount of calories consumed by customers at the Chinese buffet is normally distributed with mean 2774 and standard deviation 697. One randomly selected customer is observed to see how many calories X that customer consumes. Round all answers to 4 decimal places where possible. a. What is the distribution of X? X ~ N(,) b. Find the probability that the customer consumes less than 2396 calories. c. What proportion of the customers consume over 2970 calories? d. The Piggy...
The number of calories consumed by customers at the Chinese buffet is normally distributed with mean...
The number of calories consumed by customers at the Chinese buffet is normally distributed with mean 2631 and standard deviation 621. One randomly selected customer is observed to see how many calories X that customer consumes. Round all answers to 4 decimal places where possible. a. What is the distribution of X? X ~ N(__________,__________) b. Find the probability that the customer consumes fewer than 2363 calories.__________ c. What proportion of the customers consumed more than 2892 calories?__________
The number of calories consumed by customers at the Chinese buffet is normally distributed with mean...
The number of calories consumed by customers at the Chinese buffet is normally distributed with mean 2675 and standard deviation 573. One randomly selected customer is observed to see how many calories X that customer consumes. Round all answers to 4 decimal places where possible. a. What is the distribution of X? X ~ N ( , ) b. Find the probability that the customer consumes fewer than 2291 calories: c. What proportion of the customers more than 2935 calories?
Assume that the heights of 30,000 male students at a university are normally distributed with a...
Assume that the heights of 30,000 male students at a university are normally distributed with a mean of 68.0 inches and a standard deviation of 3.0 inches. A random sample of 35 students is taken and the mean is calculated. What is the probability that this mean value will be between 66.8 inches and 68.8 inches?
Suppose the amount spent on cell phone service for students per month is normally distributed and...
Suppose the amount spent on cell phone service for students per month is normally distributed and has a mean of $54 and a standard deviation of $9. Binomial or Normal? What is the probability that the monthly cell phone bill for a randomly selected Wake Tech student is more than $60? What is the probability that the monthly cell phone bill for a randomly selected Wake Tech student is less than $50? Most student’s bill will be in the middle...
The weight of 1000 students in a local university are normally distributed with a mean of...
The weight of 1000 students in a local university are normally distributed with a mean of 68.5kg and a standard deviation of 2.7kg. What is the probability that their weight is less than 63.0kg?        What is the probability that their weight is greater than 74.0kg? What is the probability that their weight is less than 69.0kg?                     What is the probability that their weight is between 67.5kg and 71.0kg?             
1. Sleep time per night among all university students is approximately normally distributed with a mean...
1. Sleep time per night among all university students is approximately normally distributed with a mean of 6.78 hours and a standard deviation of 1.24 hours. A random sample of 31 students is selected. Question: Calculate the value that 20 percent of the means would exceed.   
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT