The number of pizzas consumed per month by university students is normally distributed with a mean of 7 and a standard deviation of 4.
A. What proportion of students consume more than 9 pizzas per month?
Probability =
B. What is the probability that in a random sample of size 9, the mean amount of pizza consumed is more than 5 pizzas per person?
Probability =
Solution :
A.
P(x > 9) = 1 - P(x < 9)
= 1 - P[(x - ) / < (9 - 7) / 4)
= 1 - P(z < 0.5)
= 1 - 0.6915
= 0.3085
Probability = 0.3085
B.
= / n = 4 / 9 = 1.3333
P( > 5) = 1 - P( < 5)
= 1 - P[( - ) / < (5 - 7) / 1.3333]
= 1 - P(z < -1.50)
= 1 - 0.0668
= 0.9332
Probability = 0.9332
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